如何在 Bash 中解析 CSV 文件? [英] How to parse a CSV file in Bash?

问题描述

我正在编写一个很长的 Bash 脚本.我想将 CSV 文件中的单元格读取到 Bash 变量中.我可以解析行和第一列，但不能解析任何其他列.到目前为止，这是我的代码:

I'm working on a long Bash script. I want to read cells from a CSV file into Bash variables. I can parse lines and the first column, but not any other column. Here's my code so far:

  cat myfile.csv|while read line
  do
    read -d, col1 col2 < <(echo $line)
    echo "I got:$col1|$col2"
  done

它只打印第一列.作为附加测试，我尝试了以下操作:

It's only printing the first column. As an additional test, I tried the following:

read -d, x y <<(echo a,b,)

$y 是空的.所以我尝试了:

And $y is empty. So I tried:

读取 x y <<(echo a b)

而 $y 是 b.为什么?

And $y is b. Why?

推荐答案

你需要使用IFS代替-d:

while IFS=, read -r col1 col2
do
    echo "I got:$col1|$col2"
done < myfile.csv

请注意，对于通用 CSV 解析，您应该使用专门的工具，该工具可以处理带内部逗号的引用字段，以及 Bash 本身无法处理的其他问题.此类工具的示例是 cvstool 和 csvkit.

Note that for general purpose CSV parsing you should use a specialized tool which can handle quoted fields with internal commas, among other issues that Bash can't handle by itself. Examples of such tools are cvstool and csvkit.

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