获取财产从C#匿名对象 [英] Getting property from c# anonymous object

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本文介绍了获取财产从C#匿名对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在服务器上,我得到JSON对象。我使用JsonConvert将其反序列化为匿名对象。然后,我要访问的成员,但我不能做这样的事情:

 对象= jsonObj.something.something.else;

所以,我创建了以下,具有能够访问使用选择字符串数组成员的意图。然而,的getProperty()这里总是返回null。任何想法?

 私有对象recGetProperty(对象currentNode,字符串[]选择,诠释指数){
    尝试{
        类型节点类型= currentNode.GetType();
        反对nextNode = nodeType.GetProperty(选择[指数]);
        如果(指数==(selectors.Length - 1)){
            返回nextNode;
        }
        其他{
            返回recGetProperty(nextNode,选择器,索引+ 1);
        }
    }
    赶上(例外五){
        返回null;
    }
}私有对象的getProperty(对象根,字符串[]选择器){
    返回recGetProperty(根,选择器0);
}


解决方案

JsonConvert.DeserializeObject 不反序列化到匿名对象(我猜,你不使用的 JsonConvert.DeserializeAnonymousType 的)。根据JSON它返回要么 JObject JArray

1 由于 JObject 的器具的IDictionary<字符串,JToken> 你可以使用这种方式。

  JSON字符串= @{为prop1:{prop2:ABC}};JObject jsonObj = JsonConvert.DeserializeObject(JSON)作为JObject;
Console.WriteLine(jsonObj [为prop1] [prop2]);

 字符串str =(字符串)jsonObj.SelectToken(prop1.prop2);

2 如果您想使用的动态的关键字,然后

 动态jsonObj = JsonConvert.DeserializeObject(JSON);
Console.WriteLine(jsonObj.prop1.prop2);

这两种方法将打印 ABC

On a server, I get JSON objects. I use JsonConvert to deserialize them into anonymous objects. I then want to access the members, but I can't do something like:

object a = jsonObj.something.something.else;

So I created the following, with the intention of being able to access a member using an array of selector strings. However, getProperty() here always returns null. Any ideas?

private object recGetProperty(object currentNode, string[] selectors, int index) {
    try {
        Type nodeType = currentNode.GetType();
        object nextNode = nodeType.GetProperty(selectors[index]);
        if (index == (selectors.Length - 1)) {
            return nextNode;
        }
        else {
            return recGetProperty(nextNode, selectors, index + 1);
        }
    }
    catch (Exception e) {
        return null;
    }           
}

private object getProperty(object root, string[] selectors) {
    return recGetProperty(root, selectors, 0);
}

解决方案

JsonConvert.DeserializeObject does not deserialize to anonymous object (I guess, you don't use JsonConvert.DeserializeAnonymousType). Depending on json it returns either JObject or JArray.

1. Since JObject implements IDictionary<string, JToken> you can use it this way

string json = @"{prop1:{prop2:""abc""}}";

JObject jsonObj = JsonConvert.DeserializeObject(json) as JObject;
Console.WriteLine(jsonObj["prop1"]["prop2"]);

or

string str = (string)jsonObj.SelectToken("prop1.prop2");

2. If you want to use the dynamic keyword, then

dynamic jsonObj = JsonConvert.DeserializeObject(json);
Console.WriteLine(jsonObj.prop1.prop2);

Both ways will print abc

这篇关于获取财产从C#匿名对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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