是否可以取消代理 Spring bean? [英] Is it possible to unproxy a Spring bean?

问题描述

我有一个 Spring bean，比方说:

I have a Spring bean, let's say:

@TransactionAttribute(TransactionAttributeType.REQUIRED) 
public class AImpl implements A {

     public void setSomeDependency(D dependency) {
         // This setter DOES NOT BELONG to interface A
     }
}

<bean id="aImpl" class="AImpl"/>

现在我想对其进行集成测试，但首先我需要模拟依赖项 D，因为它做了太多的事情.由于AImpl实现了一个接口并且包含了一个事务注解，所以生成的代理只兼容A接口，所以我可以这样做:

Now I want to integration test it, but first I need to mock the dependency D, because it does too much stuff. Since the AImpl implements an interface and contains a transactional annotation, the generated proxy is only compatible with the interface A, so I can do this:

@Inject @Named("aImpl")
private A a;

但不能:

@Inject @Named("aImpl")
private AImpl a;

因此，我无法嘲笑我的依赖.

As a result, I can't mock my dependency.

请注意，将void setSomeDependency(D dependency) 添加到接口A 不是一种选择，因为它没有商业意义.它也没有使用 proxy-target-class="true"，因为它破坏了很多其他 bean(此属性影响上下文中的所有 bean).

Please note that adding void setSomeDependency(D dependency) to interface A is not an option, as it has no business meaning. Neither it is using the proxy-target-class="true", as it breaks a whole lot of other beans (this attribute affects all beans in the context).

有没有办法取消代理注入的 bean A，这样我就可以将它转换为 AImpl?

Is there a way to unproxy the injected bean A, so I could cast it to AImpl?

推荐答案

试试这个:

if(AopUtils.isAopProxy(a) && a instanceof Advised) {
    Object target = ((Advised)a).getTargetSource().getTarget();
    AImpl ai = (AImpl)target;
}

奖励:在 Scala 中，我出于相同的目的使用以下等效函数:

Bonus: in Scala I am using the following equivalent function for the very same purpose:

def unwrapProxy(a: AnyRef) = a match {
    case advised: Advised if(AopUtils.isAopProxy(advised)) => 
                            advised.getTargetSource.getTarget
    case notProxy => notProxy
}

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