在 Bash 中提取子字符串 [英] Extract substring in Bash

问题描述

给定一个 someletters_12345_moreleters.ext 形式的文件名，我想提取 5 位数字并将它们放入一个变量中.

Given a filename in the form someletters_12345_moreleters.ext, I want to extract the 5 digits and put them into a variable.

所以为了强调这一点，我有一个包含 x 个字符的文件名，然后是一个五位数字序列，两边各有一个下划线，然后是另一组 x 个字符.我想取 5 位数字并将其放入一个变量中.

So to emphasize the point, I have a filename with x number of characters then a five digit sequence surrounded by a single underscore on either side then another set of x number of characters. I want to take the 5 digit number and put that into a variable.

我对实现这一目标的不同方式非常感兴趣.

I am very interested in the number of different ways that this can be accomplished.

推荐答案

使用 cut:

echo 'someletters_12345_moreleters.ext' | cut -d'_' -f 2

更通用:

INPUT='someletters_12345_moreleters.ext'
SUBSTRING=$(echo $INPUT| cut -d'_' -f 2)
echo $SUBSTRING

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