如何迭代 Bash 中由变量定义的一系列数字? [英] How do I iterate over a range of numbers defined by variables in Bash?

问题描述

当范围由变量给出时，如何在 Bash 中迭代一个数字范围?

How do I iterate over a range of numbers in Bash when the range is given by a variable?

我知道我可以做到这一点(在 Bash 文档):

I know I can do this (called "sequence expression" in the Bash documentation):

 for i in {1..5}; do echo $i; done

给出:

1
2
3
4
5

1
2
3
4
5

但是，如何用变量替换任一范围端点?这不起作用:

Yet, how can I replace either of the range endpoints with a variable? This doesn't work:

END=5
for i in {1..$END}; do echo $i; done

打印:

{1..5}

推荐答案

for i in $(seq 1 $END); do echo $i; done

我更喜欢 seq 而不是其他方法，因为我真的能记住它 ;)

edit: I prefer seq over the other methods because I can actually remember it ;)

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