如何使用 Bash 抑制命令的所有输出? [英] How can I suppress all output from a command using Bash?

问题描述

我有一个运行带参数程序的 Bash 脚本.该程序输出一些状态(做这个，做那个......).这个程序没有任何选择可以安静.如何防止脚本显示任何内容?

I have a Bash script that runs a program with parameters. That program outputs some status (doing this, doing that...). There isn't any option for this program to be quiet. How can I prevent the script from displaying anything?

我正在寻找类似 Windows 的 "echo off".

I am looking for something like Windows' "echo off".

推荐答案

以下将标准输出发送到空设备(位桶).

The following sends standard output to the null device (bit bucket).

scriptname >/dev/null

如果您还希望在那里发送错误消息，请使用其中一个(第一个可能不适用于所有 shell):

And if you also want error messages to be sent there, use one of (the first may not work in all shells):

scriptname &>/dev/null
scriptname >/dev/null 2>&1
scriptname >/dev/null 2>/dev/null

并且，如果您想记录消息，但不想看到它们，请将 /dev/null 替换为实际文件，例如:

And, if you want to record the messages, but not see them, replace /dev/null with an actual file, such as:

scriptname &>scriptname.out

为了完整起见，在 Windows cmd.exe(其中nul"相当于/dev/null")下，它是:

For completeness, under Windows cmd.exe (where "nul" is the equivalent of "/dev/null"), it is:

scriptname >nul 2>nul

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