提取所有 git 子模块的最新版本的简单方法 [英] Easy way to pull latest of all git submodules

问题描述

我们正在使用 git 子模块来管理几个依赖于我们开发的许多其他库的大型项目.每个库都是一个单独的存储库，作为子模块引入依赖项目.在开发过程中，我们经常只想去抓取每个依赖子模块的最新版本.

We're using git submodules to manage a couple of large projects that have dependencies on many other libraries we've developed. Each library is a separate repo brought into the dependent project as a submodule. During development, we often want to just go grab the latest version of every dependent submodule.

git 是否有内置命令来执行此操作?如果没有，Windows 批处理文件或类似的文件如何?

Does git have a built in command to do this? If not, how about a Windows batch file or similar that can do it?

推荐答案

如果是第一次检出一个repo，你需要先使用--init:

If it's the first time you check-out a repo you need to use --init first:

git submodule update --init --recursive

git 1.8.2及以上版本，新增--remote选项，支持更新远程分支最新提示:

For git 1.8.2 or above, the option --remote was added to support updating to latest tips of remote branches:

git submodule update --recursive --remote

这有一个额外的好处，即尊重 .gitmodules 或 .git/config 文件中指定的任何非默认"分支(如果你碰巧有任何，默认是 origin/master，在这种情况下，这里的其他一些答案也适用).

This has the added benefit of respecting any "non default" branches specified in the .gitmodules or .git/config files (if you happen to have any, default is origin/master, in which case some of the other answers here would work as well).

对于 git 1.7.3 或更高版本，您可以使用(但以下关于更新的问题仍然适用):

For git 1.7.3 or above you can use (but the below gotchas around what update does still apply):

git submodule update --recursive

或:

git pull --recurse-submodules

如果你想把你的子模块拉到最新的提交而不是当前提交的 repo 指向.

if you want to pull your submodules to latest commits instead of the current commit the repo points to.

参见 git-submodule(1) 详情

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