启动新进程，而不是生成进程的子进程 [英] Start new process, without being a child of the spawning process

问题描述

如果它不是调用进程的子进程，我将如何开始一个新进程.

How would I go about starting a new process without it being the child of the calling process.

示例:

主程序(Caller.exe)

process.start("file.exe")

图片:

推荐答案

这是我现在使用的代码.我认为它可能对某人有用.它接受一个参数.参数是一个 base64 编码的字符串，可解码为您要运行的文件的路径.

Here is the code that I'm now using. I thought that it may be useful to someone. It accepts one argument. The argument is a base64 encoded string that decodes to the path of the file that you would like to run.

 Module Module1

    Sub Main()
        Dim CommandLineArgs As System.Collections.ObjectModel.ReadOnlyCollection(Of String) = My.Application.CommandLineArgs
        If CommandLineArgs.Count = 1 Then
            Try
                Dim path As String = FromBase64(CommandLineArgs(0))
                Diagnostics.Process.Start(path)
            Catch
            End Try
            End
        End If
    End Sub

    Function FromBase64(ByVal base64 As String) As String
        Dim b As Byte() = Convert.FromBase64String(base64)
        Return System.Text.Encoding.UTF8.GetString(b)
    End Function

End Module

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