C#:等待所有线程完成 [英] C#: Waiting for all threads to complete

问题描述

我在编写的代码中遇到了一个常见模式，我需要等待组中的所有线程完成并超时.超时应该是所有线程完成所需的时间，所以简单地为每个线程执行 thread.Join(timeout) 是行不通的，因为可能的超时时间是 timeout * numThreads.

I'm running into a common pattern in the code that I'm writing, where I need to wait for all threads in a group to complete, with a timeout. The timeout is supposed to be the time required for all threads to complete, so simply doing thread.Join(timeout) for each thread won't work, since the possible timeout is then timeout * numThreads.

现在我做的事情如下:

var threadFinishEvents = new List<EventWaitHandle>();

foreach (DataObject data in dataList)
{
    // Create local variables for the thread delegate
    var threadFinish = new EventWaitHandle(false, EventResetMode.ManualReset);
    threadFinishEvents.Add(threadFinish);

    var localData = (DataObject) data.Clone();
    var thread = new Thread(
        delegate()
        {
            DoThreadStuff(localData);
            threadFinish.Set();
        }
    );
    thread.Start();
}

Mutex.WaitAll(threadFinishEvents.ToArray(), timeout);

但是，对于这种事情，似乎应该有一个更简单的习语.

However, it seems like there should be a simpler idiom for this sort of thing.

推荐答案

我仍然认为使用 Join 更简单.记录预期完成时间(如Now+timeout)，然后循环执行

I still think using Join is simpler. Record the expected completion time (as Now+timeout), then, in a loop, do

if(!thread.Join(End-now))
    throw new NotFinishedInTime();

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