Java 线程安全中的 volatile int 是什么? [英] Is a volatile int in Java thread-safe?

问题描述

Java 线程安全中的易失性 int 吗?也就是说，可以在不加锁的情况下安全地读取和写入吗?

Is a volatile int in Java thread-safe? That is, can it be safely read from and written to without locking?

推荐答案

是的，您可以安全地从中读取和写入 - 但是您不能执行任何复合操作，例如安全地递增它，因为那是读取/修改/写循环.还有一个问题是它如何与对其他变量的访问进行交互.

Yes, you can read from it and write to it safely - but you can't do anything compound such as incrementing it safely, as that's a read/modify/write cycle. There's also the matter of how it interacts with access to other variables.

坦率地说，volatile 的确切性质令人困惑(请参阅 JLS 的内存模型部分以获取更多详细信息) - 我个人通常会使用 AtomicInteger，作为一种更简单的方法来确保我做对了.

The precise nature of volatile is frankly confusing (see the memory model section of the JLS for more details) - I would personally generally use AtomicInteger instead, as a simpler way of making sure I get it right.

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