如何获取列表的最后一个元素 [英] How to get the last element of a list
问题描述
在 Python 中,如何获取列表的最后一个元素?
some_list[-1]
是最短且最 Pythonic 的.
事实上,你可以用这个语法做更多的事情.some_list[-n]
语法获取倒数第 n 个元素.所以 some_list[-1]
获取最后一个元素,some_list[-2]
获取倒数第二个元素,依此类推,一直到 some_list[-len(some_list)]
,它为您提供第一个元素.
您也可以通过这种方式设置列表元素.例如:
<预><代码>>>>some_list = [1, 2, 3]>>>some_list[-1] = 5 # 设置最后一个元素>>>some_list[-2] = 3 # 设置倒数第二个元素>>>some_list[1, 3, 5]请注意,通过索引获取列表项将引发 IndexError
如果预期的项目不存在.这意味着如果 some_list
为空,some_list[-1]
将引发异常,因为空列表不能有最后一个元素.
In Python, how do you get the last element of a list?
some_list[-1]
is the shortest and most Pythonic.
In fact, you can do much more with this syntax. The some_list[-n]
syntax gets the nth-to-last element. So some_list[-1]
gets the last element, some_list[-2]
gets the second to last, etc, all the way down to some_list[-len(some_list)]
, which gives you the first element.
You can also set list elements in this way. For instance:
>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]
Note that getting a list item by index will raise an IndexError
if the expected item doesn't exist. This means that some_list[-1]
will raise an exception if some_list
is empty, because an empty list can't have a last element.
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