编码密码看起来不像 BCrypt [英] Encoded password does not look like BCrypt
本文介绍了编码密码看起来不像 BCrypt的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在使用 Spring Boot、Spring Security、OAuth2 和 JWT 来验证我的应用程序，但我不断收到这个令人讨厌的错误，我不知道出了什么问题.我的 CustomDetailsService 类:
I am using Spring Boot, Spring Security, OAuth2 and JWT to authenticate my application, but I keep getting this nasty error and I don't have any idea what is wrong. My CustomDetailsService class:
@Service
public class CustomDetailsService implements UserDetailsService {
private static final Logger logger = LoggerFactory.getLogger(CustomDetailsService.class);
@Autowired
private UserBO userBo;
@Autowired
private RoleBO roleBo;
@Override
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
AppUsers appUsers = null;
try {
appUsers = this.userBo.loadUserByUsername(username);
System.out.println("========|||=========== "+appUsers.getUsername());
}catch(IndexOutOfBoundsException e){
throw new UsernameNotFoundException("Wrong username");
}catch(DataAccessException e){
e.printStackTrace();
throw new UsernameNotFoundException("Database Error");
}catch(Exception e){
e.printStackTrace();
throw new UsernameNotFoundException("Unknown Error");
}
if(appUsers == null){
throw new UsernameNotFoundException("Bad credentials");
}
logger.info("Username: "+appUsers.getUsername());
return buildUserFromUserEntity(appUsers);
}
private User buildUserFromUserEntity(AppUsers authUsers) {
Set<UserRole> userRoles = authUsers.getUserRoles();
boolean enabled = true;
boolean accountNotExpired = true;
boolean credentialsNotExpired = true;
boolean accountNotLocked = true;
if (authUsers.getAccountIsActive()) {
try {
if(authUsers.getAccountExpired()){
accountNotExpired = true;
} else if (authUsers.getAccountIsLocked()) {
accountNotLocked = true;
} else {
if (containsRole((userRoles), roleBo.findRoleByName("FLEX_ADMIN"))){
accountNotLocked = false;
}
}
}catch(Exception e){
enabled = false;
e.printStackTrace();
}
}else {
accountNotExpired = false;
}
// convert model user to spring security user
String username = authUsers.getUsername();
String password = authUsers.getPassword();
List<GrantedAuthority> authorities = buildUserAuthority(userRoles);
User springUser = new User(username, password,enabled, accountNotExpired, credentialsNotExpired, accountNotLocked, authorities);
return springUser;
}
}
OAuth2Config:
@Configuration
public class OAuth2Config extends AuthorizationServerConfigurerAdapter {
@Autowired
private AuthenticationManager authenticationManager;
@Bean
public JwtAccessTokenConverter tokenConverter() {
JwtAccessTokenConverter tokenConverter = new JwtAccessTokenConverter();
tokenConverter.setSigningKey(PRIVATE_KEY);
tokenConverter.setVerifierKey(PUBLIC_KEY);
return tokenConverter;
}
@Bean
public JwtTokenStore tokenStore() {
return new JwtTokenStore(tokenConverter());
}
@Override
public void configure(AuthorizationServerEndpointsConfigurer endpointsConfigurer) throws Exception {
endpointsConfigurer.authenticationManager(authenticationManager)
.tokenStore(tokenStore())
.accessTokenConverter(tokenConverter());
}
@Override
public void configure(AuthorizationServerSecurityConfigurer securityConfigurer) throws Exception {
securityConfigurer.tokenKeyAccess("permitAll()").checkTokenAccess("isAuthenticated()");
}
@Override
public void configure(ClientDetailsServiceConfigurer clients) throws Exception {
clients.inMemory()
.withClient(CLIENT_ID)
.secret(CLIENT_SECRET)
.scopes("read","write")
.authorizedGrantTypes("password","refresh_token")
.accessTokenValiditySeconds(20000)
.refreshTokenValiditySeconds(20000);
}
}
SecurityConfig:
@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
CustomDetailsService customDetailsService;
@Bean
public PasswordEncoder encoder() {
return new BCryptPasswordEncoder();
}
@Override
@Autowired
protected void configure(AuthenticationManagerBuilder authenticationManagerBuilder) throws Exception {
authenticationManagerBuilder.userDetailsService(customDetailsService).passwordEncoder(encoder());
System.out.println("Done...finito");
}
@Override
protected void configure(HttpSecurity httpSecurity) throws Exception {
httpSecurity.authorizeRequests()
.anyRequest()
.authenticated()
.and()
.sessionManagement()
.sessionCreationPolicy(SessionCreationPolicy.NEVER);
}
@Override
@Bean
public AuthenticationManager authenticationManager() throws Exception {
return super.authenticationManagerBean();
}
}
没有错误信息，除了:
Hibernate: select appusers0_.id as id1_2_, appusers0_.account_expired as account_2_2_, appusers0_.account_is_active as account_3_2_, appusers0_.account_is_locked as account_4_2_, appusers0_.bank_acct as bank_acc5_2_, appusers0_.branch_id as branch_i6_2_, appusers0_.bvn as bvn7_2_, appusers0_.create_date as create_d8_2_, appusers0_.created_by as created_9_2_, appusers0_.email as email10_2_, appusers0_.email_verified_code as email_v11_2_, appusers0_.gender as gender12_2_, appusers0_.gravatar_url as gravata13_2_, appusers0_.is_deleted as is_dele14_2_, appusers0_.lastname as lastnam15_2_, appusers0_.middlename as middlen16_2_, appusers0_.modified_by as modifie17_2_, appusers0_.modified_date as modifie18_2_, appusers0_.orgnization_id as orgniza19_2_, appusers0_.password as passwor20_2_, appusers0_.phone_no as phone_n21_2_, appusers0_.surname as surname22_2_, appusers0_.token_expired as token_e23_2_, appusers0_.username as usernam24_2_ from users appusers0_ where appusers0_.username=?
Tinubu
2018-03-31 01:42:03.255 INFO 4088 --- [nio-8072-exec-2] o.a.c.c.C.[Tomcat].[localhost].[/] : Initializing Spring FrameworkServlet 'dispatcherServlet'
2018-03-31 01:42:03.255 INFO 4088 --- [nio-8072-exec-2] o.s.web.servlet.DispatcherServlet : FrameworkServlet 'dispatcherServlet': initialization started
2018-03-31 01:42:03.281 INFO 4088 --- [nio-8072-exec-2] o.s.web.servlet.DispatcherServlet : FrameworkServlet 'dispatcherServlet': initialization completed in 26 ms
2018-03-31 01:42:03.489 WARN 4088 --- [nio-8072-exec-2] o.s.s.c.bcrypt.BCryptPasswordEncoder : Encoded password does not look like BCrypt
我的实体模型类是:
@Entity
@Table(name="USERS")
@DynamicUpdate
public class AppUsers {
@Id
@Column(name="ID")
@GeneratedValue(strategy = GenerationType.IDENTITY)
@ApiModelProperty(notes = "The user auto generated identity", required = true)
private Long id;
@Column(name="username")
@ApiModelProperty(notes = "The username parameter", required = true)
private String username;
@Column(name="password")
@ApiModelProperty(notes = "The password parameter", required = true)
private String password;
@JsonManagedReference
@OneToMany(mappedBy="appUsers")
private Set<UserRole> userRoles;
'''''' setters and getters
}
Role 实体:
@Entity
@Table(name="ROLE")
public class Role {
@javax.persistence.Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "role_id", unique = true, nullable = false)
private Long Id;
@Column(name = "name")
private String roleName;
@JsonManagedReference
@OneToMany(mappedBy="role")
private Set<UserRole> userRoles;
//getters and setters
}
UserRole 实体:
@Entity
@Table(name="USER_ROLE")
@DynamicUpdate
public class UserRole implements Serializable {
private static final long serialVersionUID = 6128016096756071383L;
@Id
@Column(name="ID")
@GeneratedValue(strategy = GenerationType.IDENTITY)
@ApiModelProperty(notes = "The userrole auto generated identity", required = true)
private long id;
@JsonBackReference
@ManyToOne//(fetch=FetchType.LAZY)
private AppUsers appUsers;
@JsonBackReference
@ManyToOne//(fetch=FetchType.LAZY)
private Role role;
// getters and setters
}
我在数据库中的密码是正确加密的 Spring security BCrypt，它的数据类型是大于 60 的 varchar(255).
My password in the database is properly encrypted Spring security BCrypt and it datatype is varchar(255) which is larger than 60.
推荐答案
BCryptPasswordEncoder 在原始密码与编码密码匹配失败时显示此警告.
BCryptPasswordEncoder shows this warning when it fails to match a raw password with an encoded password.
散列密码现在可能是$2b"或$2y".
The hashed password might be "$2b" or "$2y" now.
Spring Security 中存在一个错误，它的正则表达式总是在寻找$2a".将调试点放在 BCryptPasswordEncoder.class 中的 matches() 函数上.
And there is a bug in Spring Security that has a regex always looking for "$2a". Put a debug point at the matches() function in the BCryptPasswordEncoder.class.
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