PIL 和 pygame.image [英] PIL and pygame.image

问题描述

我使用 PIL 打开了一个图像，如

I had opened an image using PIL, as

image = Image.open("SomeImage.png")

在上面画一些文字

draw = ImageDraw.Draw(image)
draw.text(Some parameters here)

然后保存为

image.save("SomeOtherName.png")

使用 pygame.image 打开它

to open it using pygame.image

this_image = pygame.image.load("SomeOtherName.png")

我只想不保存就做..这可能吗?保存然后加载需要大量时间(0.12 秒是的，因为我有多个图像需要此操作，所以更多).那个保存方法可以超越吗?

I just want to do it without saving.. Can that be possible? It is taking a lot of time to save and then load(0.12 sec Yes, that is more as I have multiple images which require this operation). Can that save method be surpassed?

推荐答案

您可以使用 pygame.image 中的 fromstring() 函数.根据文档，以下应该有效:

You could use the fromstring() function from pygame.image. The following should work, according to the documentation:

image = Image.open("SomeImage.png")
draw = ImageDraw.Draw(image)
draw.text(Some parameters here)

mode = image.mode
size = image.size
data = image.tostring()

this_image = pygame.image.fromstring(data, size, mode)

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