是否有具有固定容量和自定义比较器的 PriorityQueue 实现? [英] Is there a PriorityQueue implementation with fixed capacity and custom comparator?

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问题描述

相关问题:

我有一个非常大的数据集(超过 500 万个项目),我需要从中获取 N 个最大 的项目.最自然的方法是使用堆/优先级队列仅存储前 N 个项目.JVM(Scala/Java)优先级队列有几个很好的实现,分别是:

I have a very large data set (more than 5 millions items) and I need to get N largest items from it. The most natural way to do it is to use heap/priority queue storing only top N items. There are several good implementations of priority queue for JVM (Scala/Java), namely:

前 2 个不错,但它们存储所有项目,在我的情况下,这会产生关键的内存开销.第三(Lucene 实现)没有这样的缺点,但正如我从文档中看到的那样,它也不支持自定义比较器,这对我来说毫无用处.

First 2 are nice, but they store all the items, which in my case gives critical memory overhead. Third (Lucene implementation) doesn't have such a drawback, but as I can see from documentation it also doesn't support custom comparator, which makes it useless for me.

那么,我的问题是:是否有具有固定容量自定义比较器PriorityQueue实现?

So, my question is: Is there a PriorityQueue implementation with fixed capacity and custom comparator?

UPD.最后,我根据彼得的回答创建了自己的实现:

UPD. Finally I've created my own implementation, based on Peter's answer:

public class FixedSizePriorityQueue<E> extends TreeSet<E> {

    private int elementsLeft;

    public FixedSizePriorityQueue(int maxSize) {
        super(new NaturalComparator());
        this.elementsLeft = maxSize;
    }

    public FixedSizePriorityQueue(int maxSize, Comparator<E> comparator) {
        super(comparator);
        this.elementsLeft = maxSize;
    }


    /**
     * @return true if element was added, false otherwise
     * */
    @Override
    public boolean add(E e) {
        if (elementsLeft == 0 && size() == 0) {
            // max size was initiated to zero => just return false
            return false;
        } else if (elementsLeft > 0) {
            // queue isn't full => add element and decrement elementsLeft
            boolean added = super.add(e);
            if (added) {
                elementsLeft--;
            }
            return added;
        } else {
            // there is already 1 or more elements => compare to the least
            int compared = super.comparator().compare(e, this.first());
            if (compared == 1) {
                // new element is larger than the least in queue => pull the least and add new one to queue
                pollFirst();
                super.add(e);
                return true;
            } else {
                // new element is less than the least in queue => return false
                return false;
            }
        }
    }
}

(其中 NaturalComparator 取自 这个问题)

(where NaturalComparator is taken from this question)

推荐答案

您可以使用 SortedSet,例如带有自定义比较器的 TreeSet 并在大小达到 N 时移除最小的.

You could use a SortedSet e.g. TreeSet with a custom comparator and remove the smallest when the size reachs N.

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