ASP.NET MVC的ActionResult查看（）不改变网址 [英] ASP.NET MVC ActionResult View() not changing url

问题描述

我有一个方法...

[HttpPost]
public ActionResult Start(SomeViewModel someViewModel) { ... }

这是基于一些条件返回之类的东西回报视图（无效），视图（NOTFOUND），视图（运行，anotherViewModel）等的问题是，无论什么看法我present，URL不改变以反映新的控制器/行动。当我查看要张贴到不同的操作这就带来了一个问题。我该如何解决这个问题？

that based on some conditions returns things like return View("Invalid"), View("NotFound"), View("Run", anotherViewModel), etc. The problem is that no matter what view I present, the URL does not change to reflect the new controller/action. This poses a problem when my View wants to post to a different action. How can I fix this?

推荐答案

的查看（...）方法的不重定向，他们只是呈现出当前请求的特定视图。如果您需要在目标视图的形式特定的URL，就可以在控制器/动作细节的形式传递方式：

The View(...) methods don't redirect, they simply render out the specific view on the current request. If you need to target a specific url in the form of your view, you can pass in the controller/action details to the form method:

Html.BeginForm("action", "controller")

...等

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