将额外的参数传递给回调函数 [英] Pass an extra argument to a callback function

问题描述

我有一个函数 callWithMagic，它接受一个回调函数作为参数并用一个参数调用它.

I have a function callWithMagic which takes a callback function as a parameter and calls it with one argument.

const callWithMagic = callback => {
  const magic = getMagic();
  callback(magic);
};

我还有一个函数 processMagic，它接受两个参数:magic 和 theAnswer.

I also have a function processMagic which takes two arguments: magic and theAnswer.

const processMagic = (magic, theAnswer) => {
  someOtherMagic();
};

我想将函数 processMagic 作为参数传递给 callWithMagic，但我也想将 42 作为第二个参数传递(theAnswer) 到 processMagic.我该怎么做?

I want to pass the function processMagic as an argument to callWithMagic, but I also want to pass 42 as the second parameter (theAnswer) to processMagic. How can I do that?

callWithMagic(<what should I put here?>);

推荐答案

只需创建一个 function(magic) {} 作为包装回调:

Just create a function(magic) {} as a wrapper callback:

callWithMagic(function(magic) {
  return processMagic(magic, 42);
});

或者使用ECMAScript 6:箭头函数:

callWithMagic(magic => processMagic(magic, 42));

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