X,Y 在 C 函数中传递数组的大小 [英] X,Y passing size for the array in C function

问题描述

我已经声明了我的函数，我想从对角线 [0][0] ... [5][5] 和 [0][5] ... [5][0] 中找到最小值.我有算法，但我的问题是实际的函数头.

I've declared my function where I want to find the minimum from diagonals [0][0] ... [5][5] and [0][5]... [5][0]. I have the algorithm but my problem is with the actual function header.

我在为函数创建形式参数时遇到问题.我知道我们必须至少将数组的x[][this] 大小传递给函数，但我尝试了各种组合，甚至

I have problem with creating the formal arguments for the function. I know that we have to pass at least x[][this] size of array to the function, but I tried various combinations, even

double minimum(int size, double x[][size]){...}

double minimum(double x[][int size]){...}

第一种情况调用时报错:

The first case gives an error when calling:

minimum(10, x[][10])
error: expected expression before ']' token ` 

第二种情况在函数声明中报错:

The second case gives an error in declaration of function:

error: expected expression before 'int' 

有人能说出问题是什么(或问题是什么)?

Can someone tell what the problem is (or problems are)?

推荐答案

double minimum(int rowsize,int size, double x[rowsize][size]){...}或者干脆

double minimum(int rowsize,int size, double x[][size]){...}

所以指定 rowsize 是可选的.

So specifying rowsize is optional.

但这里我猜它是方形的size x size 所以它会是

But here I guess it is square size x size so it will be

double minimum(int size, double x[][size]){...}

所以你是对的.

最小值(10,x)

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