如何将匿名类型作为参数传递? [英] How to pass anonymous types as parameters?

问题描述

如何将匿名类型作为参数传递给其他函数?考虑这个例子:

How can I pass anonymous types as parameters to other functions? Consider this example:

var query = from employee in employees select new { Name = employee.Name, Id = employee.Id };
LogEmployees(query);

这里的变量 query 没有强类型.我应该如何定义我的 LogEmployees 函数来接受它?

The variable query here doesn't have strong type. How should I define my LogEmployees function to accept it?

public void LogEmployees (? list)
{
    foreach (? item in list)
    {

    }
}

换句话说，我应该用什么来代替 ? 标记.

In other words, what should I use instead of ? marks.

推荐答案

我认为您应该为这种匿名类型创建一个类.在我看来，这是最明智的做法.但如果你真的不想，你可以使用动态:

I think you should make a class for this anonymous type. That'd be the most sensible thing to do in my opinion. But if you really don't want to, you could use dynamics:

public void LogEmployees (IEnumerable<dynamic> list)
{
    foreach (dynamic item in list)
    {
        string name = item.Name;
        int id = item.Id;
    }
}

请注意，这是不是强类型的，因此，例如，如果 Name 更改为 EmployeeName，直到运行时您才会知道有问题.

Note that this is not strongly typed, so if, for example, Name changes to EmployeeName, you won't know there's a problem until runtime.

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