函数返回自身 [英] Function Returning Itself

问题描述

是否可以声明一些函数类型 func_t 返回该类型，func_t?

Is it possible to declare some function type func_t which returns that type, func_t?

换句话说，函数是否有可能返回自身?

In other words, is it possible for a function to return itself?

// func_t is declared as some sort of function pointer
func_t foo(void *arg)
{
  return &foo;
}

或者我必须使用 void * 和类型转换?

Or would I have to use void * and typecasting?

推荐答案

不，您不能在 C 中声明递归函数类型.除了在结构(或联合)内部，不可能在 C 中声明递归类型.

No, you cannot declare recursive function types in C. Except inside a structure (or an union), it's not possible to declare a recursive type in C.

现在对于 void * 解决方案，void * 只能保证保存指向对象的指针，而不是指向函数的指针.能够转换函数指针和 void * 仅作为扩展可用.

Now for the void * solution, void * is only guaranteed to hold pointers to objects and not pointers to functions. Being able to convert function pointers and void * is available only as an extension.

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