在另一个函数完成后执行 jQuery 函数 [英] Execute jQuery function after another function completes
问题描述
我想在另一个自定义函数完成后执行一个自定义 jQuery 函数
第一个函数用于创建打字"效果
function Typer(){var srcText = '示例';变量 i = 0;var 结果 = srcText[i];设置间隔(函数(){如果(我 == srcText.length){clearInterval(this);返回;};我++;结果 += srcText[i].replace("
", "
");$("#message").html(结果);},100);}
第二个函数播放声音
函数 playBGM(){document.getElementById('bgm').play();}
我一个接一个地调用函数
打字机();播放BGM();
但是随着文本的输入,声音开始播放.我只想在打字完成后播放声音.
这是我尝试过的:http://jsfiddle.net/GkUEN/5/
我该如何解决这个问题?
你应该使用回调参数:
function Typer(回调){var srcText = '示例';变量 i = 0;var 结果 = srcText[i];var 间隔 = setInterval(function() {如果(我 == srcText.length - 1){清除间隔(间隔);打回来();返回;}我++;结果 += srcText[i].replace("
", "
");$("#message").html(result);},100);返回真;}功能播放BGM(){alert("播放BGM功能");$('#bgm').get(0).play();}打字机(函数(){播放BGM();});//或单行:Typer(playBGM);
因此,您传递一个函数作为参数(callback
),该函数将在 return
之前在 if
中调用.
此外,this 是一篇关于回调的好文章.
function Typer(callback){var srcText = '示例';变量 i = 0;var 结果 = srcText[i];var 间隔 = setInterval(function() {如果(我 == srcText.length - 1){清除间隔(间隔);打回来();返回;}我++;结果 += srcText[i].replace("
", "
");$("#message").html(result);},100);返回真;}功能播放BGM(){alert("播放BGM功能");$('#bgm').get(0).play();}打字机(函数(){播放BGM();});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script><div id="消息">
<audio id="bgm" src="http://www.freesfx.co.uk/rx2/mp3s/9/10780_1381246351.mp3"></audio>
I want to execute a custom jQuery function after another custom function completes
The first function is used for creating a "typewriting" effect
function Typer()
{
var srcText = 'EXAMPLE ';
var i = 0;
var result = srcText[i];
setInterval(function() {
if(i == srcText.length) {
clearInterval(this);
return;
};
i++;
result += srcText[i].replace("
", "<br />");
$("#message").html( result);
},
100);
}
and the second function plays a sound
function playBGM()
{
document.getElementById('bgm').play();
}
I am calling the functions one after the another like
Typer();
playBGM();
But the sound starts playing as the text is getting typed. I want to play the sound only AFTER the typewriting has finished.
Here is what I have tried: http://jsfiddle.net/GkUEN/5/
How can I fix this?
You should use a callback parameter:
function Typer(callback)
{
var srcText = 'EXAMPLE ';
var i = 0;
var result = srcText[i];
var interval = setInterval(function() {
if(i == srcText.length - 1) {
clearInterval(interval);
callback();
return;
}
i++;
result += srcText[i].replace("
", "<br />");
$("#message").html(result);
},
100);
return true;
}
function playBGM () {
alert("Play BGM function");
$('#bgm').get(0).play();
}
Typer(function () {
playBGM();
});
// or one-liner: Typer(playBGM);
So, you pass a function as parameter (callback
) that will be called in that if
before return
.
Also, this is a good article about callbacks.
function Typer(callback)
{
var srcText = 'EXAMPLE ';
var i = 0;
var result = srcText[i];
var interval = setInterval(function() {
if(i == srcText.length - 1) {
clearInterval(interval);
callback();
return;
}
i++;
result += srcText[i].replace("
", "<br />");
$("#message").html(result);
},
100);
return true;
}
function playBGM () {
alert("Play BGM function");
$('#bgm').get(0).play();
}
Typer(function () {
playBGM();
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<div id="message">
</div>
<audio id="bgm" src="http://www.freesfx.co.uk/rx2/mp3s/9/10780_1381246351.mp3">
</audio>
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