$之间的区别?和 $LastExitCode 在 PowerShell 中 [英] Difference between $? and $LastExitCode in PowerShell
问题描述
在 PowerShell 中,$?
和 $LastExitCode
有什么区别?
我阅读了关于自动变量,它说:><块引用>
<代码>$?包含上次操作的执行状态.如果上次操作成功,则包含 TRUE,如果失败则包含 FALSE.
$LastExitCode 包含最后运行的基于 Windows 的程序的退出代码.
在$?
的定义中,它没有解释成功和失败的含义.
我问是因为我假设 $?
为 True 当且仅当 $LastExitCode 为 0,但我发现了一个令人惊讶的反例:$LastExitCode=0 但 $?=False 在 PowerShell 中.将 stderr 重定向到 stdout 会导致 NativeCommandError.
$LastExitCode
是本机应用程序的返回码.$?
仅返回 True
或 False
取决于最后一个命令(cmdlet 或本机)是否正确退出.
对于 cmdlet 失败通常意味着异常,对于本机应用程序,它是一个非零退出代码:
PS>cmd/c "退出 5"PS>$?错误的PS>cmd/c "退出 0"PS>$?真的
使用 Ctrl+C 取消 cmdlet 也算作失败;对于本机应用程序,这取决于它们设置的退出代码.
In PowerShell, what is the difference between $?
and $LastExitCode
?
I read about automatic variables, and it said:
$? Contains the execution status of the last operation. It contains TRUE if the last operation succeeded and FALSE if it failed.
$LastExitCode Contains the exit code of the last Windows-based program that was run.
In the definition of $?
it doesn't explain what succeed and fail mean.
I ask because I presumed that $?
is True if and only if $LastExitCode is 0, but I found a surprising counter-example: $LastExitCode=0 but $?=False in PowerShell. Redirecting stderr to stdout gives NativeCommandError.
$LastExitCode
is the return code of native applications. $?
just returns True
or False
depending on whether the last command (cmdlet or native) exited without error or not.
For cmdlets failure usually means an exception, for native applications it's a non-zero exit code:
PS> cmd /c "exit 5"
PS> $?
False
PS> cmd /c "exit 0"
PS> $?
True
Cancelling a cmdlet with Ctrl+C will also count as failure; for native applications it depends on what exit code they set.
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