你如何检查一个数字是否可以被另一个数字整除(Python)? [英] How do you check whether a number is divisible by another number (Python)?

问题描述

我需要测试从 1 到 1000 的每个数字是 3 的倍数还是 5 的倍数.我认为这样做的方法是将数字除以 3，如果结果是整数那么它将是 3 的倍数.与 5 相同.

I need to test whether each number from 1 to 1000 is a multiple of 3 or a multiple of 5. The way I thought I'd do this would be to divide the number by 3, and if the result is an integer then it would be a multiple of 3. Same with 5.

如何测试数字是否为整数?

How do I test whether the number is an integer?

这是我当前的代码:

n = 0
s = 0

while (n < 1001):
    x = n/3
    if isinstance(x, (int, long)):
        print 'Multiple of 3!'
        s = s + n
    if False:
        y = n/5
        if isinstance(y, (int, long)):
            s = s + n

    print 'Number: '
    print n
    print 'Sum:'
    print s
    n = n + 1

推荐答案

您可以使用模数运算符 %

You do this using the modulus operator, %

n % k == 0

当且仅当 n 是 k 的精确倍数时才计算为真.在初等数学中，这被称为除法的余数.

evaluates true if and only if n is an exact multiple of k. In elementary maths this is known as the remainder from a division.

在您当前的方法中，您执行除法，结果将是

In your current approach you perform a division and the result will be either

• 如果使用整数除法，则始终为整数，或
• 如果使用浮点除法，则始终为浮点数.

这只是测试可分性的错误方法.

It's just the wrong way to go about testing divisibility.

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