正文中的 Android Volley POST 字符串 [英] Android Volley POST string in body

问题描述

我正在尝试使用 Volley 库与我的 RESTful API 进行通信.

I'm trying to use Volley library to communicate with my RESTful API.

当我要求不记名令牌时，我必须在正文中 POST 字符串.字符串应如下所示:grant_type=password&username=Alice&password=password123和标题:内容类型:application/x-www-form-urlencoded

I have to POST string in the body, when I'm asking for the bearer Token. String should look like this: grant_type=password&username=Alice&password=password123 And header: Content-Type: application/x-www-form-urlencoded

有关 WebApi 个人帐户的更多信息:http://www.asp.net/web-api/overview/security/individual-accounts-in-web-api

More info about WebApi Individual Accounts: http://www.asp.net/web-api/overview/security/individual-accounts-in-web-api

不幸的是，我不知道如何解决它..

Unfortunately I can't figure out how can I solve it..

我正在尝试这样的事情:

I'm trying something like this:

StringRequest req = new StringRequest(Request.Method.POST, URL, new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {
                        VolleyLog.v("Response:%n %s", response);
                    }
                }, new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        VolleyLog.e("Error: ", error.getMessage());
                    }
                }){
                    @Override
                    protected Map<String, String> getParams() throws AuthFailureError {
                        Map<String, String> params = new HashMap<String, String>();
                        params.put("grant_type", "password");
                        params.put("username", "User0");
                        params.put("password", "Password0");
                        return params;
                    }

                    @Override
                    public Map<String, String> getHeaders() throws AuthFailureError {
                        Map<String, String> headers = new HashMap<String, String>();
                        headers.put("Content-Type", "application/x-www-form-urlencoded");
                        return headers;
                    }
                };

我一直收到 400 个错误请求.我认为我实际上是在发送这样的请求:

I'm getting 400 Bad Request all the time. I think that I'm actually sending request like this:

grant_type:password, username:User0, password:Password0

代替:

grant_type=password&username=Alice&password=password123

如果有人有任何想法或建议，我将不胜感激..

I would be very grateful if anyone has any ideas or an advice..

推荐答案

首先，我建议您通过打印到日志或使用诸如wireshark 或 fiddler 之类的网络嗅探器来准确查看您发送的内容.

First thing, I advise you to see exactly what you're sending by either printing to the log or using a network sniffer like wireshark or fiddler.

尝试将参数放入正文怎么样?如果您仍然需要 StringRequest，则需要扩展它并覆盖 getBody() 方法(类似于 JsonObjectRequest)

How about trying to put the params in the body? If you still want a StringRequest you'll need to extend it and override the getBody() method (similarly to JsonObjectRequest)

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