如何仅在丢失的路由上将 Express.js 设置为 404? [英] How can I get Express.js to 404 only on missing routes?
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问题描述
目前,我有以下所有其他路线:
At the moment I have the following which sits below all my other routes:
app.get('*', function(req, res){
console.log('404ing');
res.render('404');
});
并且根据日志,即使路由在上面匹配,它也会被触发.我怎样才能让它只在没有匹配的情况下触发?
And according to the logs, it is being fired even when the route is being matched above. How can I get it to only fire when nothing is matched?
推荐答案
你只需要把它放在所有路由的末尾.
You just need to put it at the end of all route.
看一下传递路由控制的第二个例子:>
Take a look at the second example of Passing Route Control:
var express = require('express')
, app = express.createServer();
var users = [{ name: 'tj' }];
app.all('/user/:id/:op?', function(req, res, next){
req.user = users[req.params.id];
if (req.user) {
next();
} else {
next(new Error('cannot find user ' + req.params.id));
}
});
app.get('/user/:id', function(req, res){
res.send('viewing ' + req.user.name);
});
app.get('/user/:id/edit', function(req, res){
res.send('editing ' + req.user.name);
});
app.put('/user/:id', function(req, res){
res.send('updating ' + req.user.name);
});
app.get('*', function(req, res){
res.send('what???', 404);
});
app.listen(3000);
或者你什么都不做,因为所有不匹配的路由都会产生 404.然后你可以使用这个代码来显示正确的模板:
Alternatively you can do nothing because all route which does not match will produce a 404. Then you can use this code to display the right template:
app.error(function(err, req, res, next){
if (err instanceof NotFound) {
res.render('404.jade');
} else {
next(err);
}
});
它记录在错误处理中.
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