如何在忽略转义逗号的同时拆分逗号分隔的字符串? [英] How to split a comma separated String while ignoring escaped commas?

问题描述

我需要编写 StringUtils.commaDelimitedListToStringArray 函数的扩展版本，该函数获得一个附加参数:转义字符.

I need to write a extended version of the StringUtils.commaDelimitedListToStringArray function which gets an additional parameter: the escape char.

所以叫我的:

commaDelimitedListToStringArray("test,test\,test\,test,test", "\")

应该返回:

["test", "test,test,test", "test"]

我目前的尝试是使用 String.split() 使用正则表达式拆分字符串:

My current attempt is to use String.split() to split the String using regular expressions:

String[] array = str.split("[^\\],");

但是返回的数组是:

["tes", "test,test,tes", "test"]

有什么想法吗?

推荐答案

正则表达式

[^\],

表示匹配一个不是反斜杠后跟逗号的字符"——这就是为什么诸如 t, 之类的模式匹配的原因，因为 t 是一个字符不是反斜杠.

means "match a character which is not a backslash followed by a comma" - this is why patterns such as t, are matching, because t is a character which is not a backslash.

我认为你需要使用某种负向后视，来捕捉, 前面没有 而不捕获前面的字符，类似于

I think you need to use some sort of negative lookbehind, to capture a , which is not preceded by a without capturing the preceding character, something like

(?<!\),

(顺便说一句，请注意，我故意没有对反斜杠进行双重转义以使其更具可读性)

(BTW, note that I have purposefully not doubly-escaped the backslashes to make this more readable)

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