如何在命令行中覆盖 maven 属性? [英] How to override maven property in command line?

问题描述

我有以下由 Maven 3.0.4 运行的普通 pom.

I have the following plain pom running by Maven 3.0.4.

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>

    <groupId>com.example</groupId>
    <artifactId>test</artifactId>
    <version>1.0</version>
    <packaging>jar</packaging>

</project>

我正在尝试像这样覆盖命令行中的默认设置:

I am trying to override default settings in command line like this:

mvn -Dproject.build.finalName=build clean package

但这被忽略了，我得到了 test-1.0.jar.我尝试更改其他属性，例如 outputDirectory、目录、artifactId，但也失败了.

But this this is ignored, and I get test-1.0.jar. I've tried to change another properties, like outputDirectory, directory, artifactId, but also failed.

做这件事的正确方法是什么?

What is the proper way to do this thing?

推荐答案

参见 Introduction toPOM

finalName 被创建为:

finalName is created as:

<build>
    <finalName>${project.artifactId}-${project.version}</finalName>
</build>

解决方案之一是添加自己的属性:

One of the solutions is to add own property:

<properties>
    <finalName>${project.artifactId}-${project.version}</finalName>
</properties>
<build>
    <finalName>${finalName}</finalName>
 </build>

现在试试:

mvn -DfinalName=构建干净的包

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