读取 Python 文件中的行时跳过前几行 [英] Skip first couple of lines while reading lines in Python file

问题描述

我想在阅读文本文件时跳过前 17 行.

假设文件如下所示:

<预><代码>00000000000000000好东西

我只想要好东西.我正在做的事情要复杂得多，但这是我遇到麻烦的部分.

解决方案

使用切片，如下所示:

 with open('yourfile.txt') as f:lines_after_17 = f.readlines()[17:]

<小时>

如果文件太大而无法加载到内存中:

 with open('yourfile.txt') as f:对于 _ 范围(17):下一个(f)对于 f 中的行:# 做东西

I want to skip the first 17 lines while reading a text file.

Let's say the file looks like:

0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
0
good stuff

I just want the good stuff. What I'm doing is a lot more complicated, but this is the part I'm having trouble with.

解决方案

Use a slice, like below:

with open('yourfile.txt') as f:
    lines_after_17 = f.readlines()[17:]

---

If the file is too big to load in memory:

with open('yourfile.txt') as f:
    for _ in range(17):
        next(f)
    for line in f:
        # do stuff

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