Move_uploaded_file() 函数不起作用 [英] Move_uploaded_file() function is not working
本文介绍了Move_uploaded_file() 函数不起作用的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我正在开发一个网站，我希望用户能够上传文件.所以我正在努力学习如何做到这一点.我研究了一下，它说我必须使用函数 move_uploaded_file().我编写的代码就像在示例中一样(更改数据)，但它不起作用.请帮助我，我是这些新手.这是我到目前为止所做的:
I'm working on a website and I want the user to be able to upload files. So I'm trying to learn how to do that. I researched and it said that I had to use the function move_uploaded_file(). I wrote the code just like it was on the example (changing the data), but it wouldn't work. Please help me, I'm new at these. Here's what I've done so far:
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<form action="upload_file.php" method="POST" enctype="multipart/form-data">
<input type="hidden" name="MAX_FILE_SIZE" value="30000" />
<input type="file"name="file">
<input type="submit">
</form>
</body>
<html>
这是upload_file.php:
This is the upload_file.php:
<!DOCTYPE html>
<html>
<head>
<head>
<body>
<?php
$move = "/Users/George/Desktop/uploads/";
echo $_FILES["file"]['name']."<br>";
echo $_FILES["file"]['tmp_name']."<br>";
echo $_FILES["file"]['size']."<br>";
echo $_FILES['file']['error']."<br>";
move_uploaded_file($_FILES['file']['name'], $move);
?>
<body>
<html>
推荐答案
该文件将被存储在一个临时位置，因此使用 tmp_name 而不是 name:>
The file will be stored in a temporary location, so use tmp_name instead of name:
if (move_uploaded_file($_FILES['image']['tmp_name'], __DIR__.'/../../uploads/'. $_FILES["image"]['name'])) {
echo "Uploaded";
} else {
echo "File not uploaded";
}
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