如何让 PHP 类构造函数调用其父级的父级构造函数? [英] How do I get a PHP class constructor to call its parent's parent's constructor?
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问题描述
我需要在 PHP 中有一个类构造函数调用其父级的父级(祖父级?)构造函数,而不调用父级构造函数.
I need to have a class constructor in PHP call its parent's parent's (grandparent?) constructor without calling the parent constructor.
// main class that everything inherits
class Grandpa
{
public function __construct()
{
}
}
class Papa extends Grandpa
{
public function __construct()
{
// call Grandpa's constructor
parent::__construct();
}
}
class Kiddo extends Papa
{
public function __construct()
{
// THIS IS WHERE I NEED TO CALL GRANDPA'S
// CONSTRUCTOR AND NOT PAPA'S
}
}
我知道这是一件很奇怪的事情,我正在尝试找到一种不难闻的方法,但尽管如此,我很好奇是否有可能.
I know this is a bizarre thing to do and I'm attempting to find a means that doesn't smell bad but nonetheless, I'm curious if it's possible.
推荐答案
丑陋的解决方法是将布尔参数传递给 Papa,表明您不希望解析其构造函数中包含的代码.即:
The ugly workaround would be to pass a boolean param to Papa indicating that you do not wish to parse the code contained in it's constructor. i.e:
// main class that everything inherits
class Grandpa
{
public function __construct()
{
}
}
class Papa extends Grandpa
{
public function __construct($bypass = false)
{
// only perform actions inside if not bypassing
if (!$bypass) {
}
// call Grandpa's constructor
parent::__construct();
}
}
class Kiddo extends Papa
{
public function __construct()
{
$bypassPapa = true;
parent::__construct($bypassPapa);
}
}
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