带有冒号分隔符的时区的 Java SimpleDateFormat? [英] Java SimpleDateFormat for time zone with a colon separator?

问题描述

我的日期格式如下:2010-03-01T00:00:00-08:00

我已经抛出以下 SimpleDateFormats 来解析它:

I have thrown the following SimpleDateFormats at it to parse it:

private static final SimpleDateFormat[] FORMATS = {
        new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ"), //ISO8601 long RFC822 zone
        new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssz"), //ISO8601 long long form zone
        new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss"), //ignore timezone
        new SimpleDateFormat("yyyyMMddHHmmssZ"), //ISO8601 short
        new SimpleDateFormat("yyyyMMddHHmm"),
        new SimpleDateFormat("yyyyMMdd"), //birthdate from NIST IHE C32 sample
        new SimpleDateFormat("yyyyMM"),
        new SimpleDateFormat("yyyy") //just the year
    };

我有一个使用这些格式的便捷方法，如下所示:

I have a convenience method that uses those formats like so:

public static Date figureOutTheDamnDate(String wtf) {
    if (wtf == null) {
        return null;
    }
    Date retval = null;
    for (SimpleDateFormat sdf : FORMATS) {
        try {
            sdf.setLenient(false)
            retval = sdf.parse(wtf);
            System.out.println("Date:" + wtf + " hit on pattern:" + sdf.toPattern());
            break;
        } catch (ParseException ex) {
            retval = null;
            continue;
        }
    }

    return retval;
}

它似乎符合 yyyyMMddHHmm 模式，但返回日期为 Thu Dec 03 00:01:00 PST 2009.

It seems to hit on the pattern yyyyMMddHHmm but returns the date as Thu Dec 03 00:01:00 PST 2009.

解析这个日期的正确模式是什么?

What is the correct pattern to parse this date?

更新:我不需要时区解析.我不希望有时间敏感问题在区域之间移动，但是我将如何解析-08:00"区域格式????

UPDATE: I don't NEED the time zone parsing. I don't anticipate having time sensitive issues moving between zones, but how would I get the "-08:00" zone format to parse????

单元测试:

@Test
public void test_date_parser() {
    System.out.println("
test_date_parser");
    //month is zero based, are you effing kidding me
    Calendar d = new GregorianCalendar(2000, 3, 6, 13, 00, 00);
    assertEquals(d.getTime(), MyClass.figureOutTheDamnDate("200004061300"));
    assertEquals(new GregorianCalendar(1950, 0, 1).getTime(), MyClass.figureOutTheDamnDate("1950"));
    assertEquals(new GregorianCalendar(1997, 0, 1).getTime(),  MyClass.figureOutTheDamnDate("199701"));
    assertEquals(new GregorianCalendar(2010, 1, 25, 15, 19, 44).getTime(),   MyClass.figureOutTheDamnDate("20100225151944-0800"));

    //my machine happens to be in GMT-0800
    assertEquals(new GregorianCalendar(2010, 1, 15, 13, 15, 00).getTime(),MyClass.figureOutTheDamnDate("2010-02-15T13:15:00-05:00"));
    assertEquals(new GregorianCalendar(2010, 1, 15, 18, 15, 00).getTime(), MyClass.figureOutTheDamnDate("2010-02-15T18:15:00-05:00"));

    assertEquals(new GregorianCalendar(2010, 2, 1).getTime(), MyClass.figureOutTheDamnDate("2010-03-01T00:00:00-08:00"));
    assertEquals(new GregorianCalendar(2010, 2, 1, 17, 0, 0).getTime(), MyClass.figureOutTheDamnDate("2010-03-01T17:00:00-05:00"));
}

单元测试的输出:

test_date_parser
Date:200004061300 hit on pattern:yyyyMMddHHmm
Date:1950 hit on pattern:yyyy
Date:199701 hit on pattern:yyyyMM
Date:20100225151944-0800 hit on pattern:yyyyMMddHHmmssZ
Date:2010-02-15T13:15:00-05:00 hit on pattern:yyyy-MM-dd'T'HH:mm:ss
Date:2010-02-15T18:15:00-05:00 hit on pattern:yyyy-MM-dd'T'HH:mm:ss
Date:2010-03-01T00:00:00-08:00 hit on pattern:yyyy-MM-dd'T'HH:mm:ss
Date:2010-03-01T17:00:00-05:00 hit on pattern:yyyy-MM-dd'T'HH:mm:ss

推荐答案

JodaTime 的 DateTimeFormat 到救援:

JodaTime's DateTimeFormat to rescue:

String dateString = "2010-03-01T00:00:00-08:00";
String pattern = "yyyy-MM-dd'T'HH:mm:ssZ";
DateTimeFormatter dtf = DateTimeFormat.forPattern(pattern);
DateTime dateTime = dtf.parseDateTime(dateString);
System.out.println(dateTime); // 2010-03-01T04:00:00.000-04:00

(toString() 中的时间和时区差异只是因为我在 GMT-4 并且没有明确设置语言环境)

(time and timezone difference in toString() is just because I'm at GMT-4 and didn't set locale explicitly)

如果你想以 java.util.Date 结束，只需使用 DateTime#toDate():

If you want to end up with java.util.Date just use DateTime#toDate():

Date date = dateTime.toDate();

等待 JDK7 (JSR-310) JSR-310，引用实现被称为ThreeTen(希望它能让如果您想在标准 Java SE API 中使用更好的格式化程序，请将其转换为 Java 8.当前的 SimpleDateFormat 确实不吃时区符号中的冒号.

Wait for JDK7 (JSR-310) JSR-310, the referrence implementation is called ThreeTen (hopefully it will make it into Java 8) if you want a better formatter in the standard Java SE API. The current SimpleDateFormat indeed doesn't eat the colon in the timezone notation.

更新:根据更新，您显然不需要时区.这应该适用于 SimpleDateFormat.只需在模式中省略它(Z)即可.

Update: as per the update, you apparently don't need the timezone. This should work with SimpleDateFormat. Just omit it (the Z) in the pattern.

String dateString = "2010-03-01T00:00:00-08:00";
String pattern = "yyyy-MM-dd'T'HH:mm:ss";
SimpleDateFormat sdf = new SimpleDateFormat(pattern);
Date date = sdf.parse(dateString);
System.out.println(date); // Mon Mar 01 00:00:00 BOT 2010

(根据我的时区是正确的)

(which is correct as per my timezone)

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