如何在 symfony2 控制器中发送 JSON 响应 [英] How can I send JSON response in symfony2 controller
问题描述
我正在使用 jQuery 来编辑我的表单，该表单内置于 Symfony.
I am using jQuery to edit my form which is built in Symfony.
我在 jQuery 对话框中显示表单，然后提交.
I am showing the form in jQuery dialog and then submitting it.
数据正确输入到数据库中.
Data is entering correctly in database.
但我不知道是否需要将一些 JSON 发送回 jQuery.其实我对 JSON 的东西有点困惑.
But I don't know whether I need to send some JSON back to jQuery. Actually I am bit confused with JSON thing.
假设我用``jQuery 在我的表中添加了一行，当我提交表单时，在提交数据后，我想发回这些行数据，以便我可以动态添加表行以显示添加的数据.
Suppose I have added a row in my table with ``jQuery and when I submit the form then after data is submitted I want to send back those row data so that I can dynamically add the table row to show the data added.
我很困惑如何取回这些数据.
I am confused how can get that data back.
这是我当前的代码:
$editForm = $this->createForm(new StepsType(), $entity);
$request = $this->getRequest();
$editForm->bindRequest($request);
if ($editForm->isValid()) {
$em->persist($entity);
$em->flush();
return $this->render('::success.html.twig');
}
这只是带有成功消息的模板.
This is just the template with success message.
推荐答案
Symfony 2.1
$response = new Response(json_encode(array('name' => $name)));
$response->headers->set('Content-Type', 'application/json');
return $response;
<小时>
Symfony 2.2 及更高版本
您有特殊的 JsonResponse将数组序列化为 JSON 的类:
You have special JsonResponse class, which serialises array to JSON:
return new JsonResponse(array('name' => $name));
<小时>
但如果你的问题是如何序列化实体，那么你应该看看JMSSerializerBundle
假设你已经安装了它，你只需要做
Assuming that you have it installed, you'll have simply to do
$serializedEntity = $this->container->get('serializer')->serialize($entity, 'json');
return new Response($serializedEntity);
您还应该检查 StackOverflow 上的类似问题:
You should also check for similar problems on StackOverflow:
这篇关于如何在 symfony2 控制器中发送 JSON 响应的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
