如何在迭代时从 HashMap 中删除一个键? [英] How to remove a key from HashMap while iterating over it?
本文介绍了如何在迭代时从 HashMap 中删除一个键?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个名为 testMap
的 HashMap
,其中包含 String, String
.
I am having HashMap
called testMap
which contains String, String
.
HashMap<String, String> testMap = new HashMap<String, String>();
迭代地图时,如果value
与指定的字符串匹配,我需要从地图中删除键.
When iterating the map, if value
is match with specified string, I need to remove the key from map.
即
for(Map.Entry<String, String> entry : testMap.entrySet()) {
if(entry.getValue().equalsIgnoreCase("Sample")) {
testMap.remove(entry.getKey());
}
}
testMap
包含 "Sample"
但我无法从 HashMap
中删除密钥.
反而出现错误:
testMap
contains "Sample"
but I am unable to remove the key from HashMap
.
Instead getting error :
"Exception in thread "main" java.util.ConcurrentModificationException
at java.util.HashMap$HashIterator.nextEntry(Unknown Source)
at java.util.HashMap$EntryIterator.next(Unknown Source)
at java.util.HashMap$EntryIterator.next(Unknown Source)"
推荐答案
尝试:
Iterator<Map.Entry<String,String>> iter = testMap.entrySet().iterator();
while (iter.hasNext()) {
Map.Entry<String,String> entry = iter.next();
if("Sample".equalsIgnoreCase(entry.getValue())){
iter.remove();
}
}
使用 Java 1.8 及更高版本,您只需一行即可完成上述操作:
With Java 1.8 and onwards you can do the above in just one line:
testMap.entrySet().removeIf(entry -> "Sample".equalsIgnoreCase(entry.getValue()));
这篇关于如何在迭代时从 HashMap 中删除一个键?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文