将列表转换为字典 [英] Convert list into a dictionary

问题描述

l = ["a", "b", "c", "d", "e"]

我想将此列表转换为字典，例如:

I want to convert this list to a dictionary like:

d = {"a": "b", "c": "d", "e": ""}

所以基本上，偶数将是关键，而赔率将是值.我知道我可以用非 Pythonic"的方式来做到这一点，比如带有 if 语句的 for 循环，但我相信应该有一种更pythonic"的方式来实现这一点.所以，我感谢任何帮助:)

So basically, the evens will be keys whereas the odds will be values. I know that I can do it in a "non-pythonic" way such as a for loop with if statements but I believe that there should be a more "pythonic" way to accomplish this. So, I appreciate any help :)

推荐答案

使用通常的 grouper食谱，你可以这样做:

Using the usual grouper recipe, you could do:

Python 2:

d = dict(itertools.izip_longest(*[iter(l)] * 2, fillvalue=""))

Python 3:

d = dict(itertools.zip_longest(*[iter(l)] * 2, fillvalue=""))

这篇关于将列表转换为字典的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！