Kotlin:使用 lambda 代替函数式接口? [英] Kotlin: Use a lambda in place of a functional interface?
问题描述
在Java中我们可以这样做Events.handler(Handshake.class, hs -> out.println(hs));
In Java we can do this
Events.handler(Handshake.class, hs -> out.println(hs));
然而,在 Kotlin 中,我试图复制行为来替换它:
In Kotlin however I am trying to replicate the behavior to replace this:
Events.handler(Handshake::class, object : EventHandler<Handshake> {
override fun handle(event: Handshake) {
println(event.sent)
}
})
用起来更方便:
Events.handler(Handshake::class, EventHandler
出于某种原因参考EventHandler
:
更可取的是,我想使用更短的东西:Events.handler(Handshake::class, { println(it.sent) })
More preferably however I'd like to use something even shorter like this:
Events.handler(Handshake::class, { println(it.sent) })
或者使用宣传的功能来使用这样的方法:Events.handler(Handshake::class) { println(it.sent) }
Or use the advertised feature to use the method like this:
Events.handler(Handshake::class) { println(it.sent) }
这是我的 Events
对象:
import java.util.*
import kotlin.reflect.KClass
object Events {
private val map = HashMap<Class<*>, Set<EventHandler<*>>>()
fun <T : Any> handler(eventType: KClass<T>, handler: EventHandler<T>) {
handler(eventType.java, handler)
}
fun <T> handler(eventType: Class<T>, handler: EventHandler<T>) = handlers(eventType).add(handler)
fun post(event: Any) = handlers(event.javaClass).forEach { it.handle(event) }
operator fun plus(event: Any) = post(event)
private fun <T> handlers(eventType: Class<T>): HashSet<EventHandler<T>> {
var set = map[eventType]
if (set == null) {
set = HashSet<EventHandler<*>>()
map.put(eventType, set)
}
return set as HashSet<EventHandler<T>>
}
}
还有我的 EventHandler
接口:
@FunctionalInterface
interface EventHandler<T> {
fun handle(event: T)
}
推荐答案
自从@andrey-breslav 发布答案以来,Kotlin 发生了很多好事.他提到:
A lot of nice things has happened to Kotlin since @andrey-breslav posted the answer. He mentions:
这是 Kotlin 只对定义的函数进行 SAM 转换爪哇.由于 Events.handler 是在 Kotlin 中定义的,因此 SAM 转换可以不适用于它.
It is that Kotlin only does SAM-conversion for functions defined in Java. Since Events.handler is defined in Kotlin, SAM-conversions do not apply to it.
好吧,Kotlin 不再是这种情况1.4+.如果您将接口标记为功能性"接口,它可以对 Kotlin 函数使用 SAM 转换:
Well, that's no longer the case for Kotlin 1.4+. It can use SAM-conversion for Kotlin functions if you mark an interface as a "functional" interface:
// notice the "fun" keyword
fun interface EventHandler<T> {
fun handle(event: T)
}
您可以在此处阅读 YouTrack 票:https://youtrack.jetbrains.com/issue/KT-7770.还有一个解释,为什么 Kotlin 需要一个与 Java 不同的接口的标记(@FunctionalInterface
只是提供信息,对编译器没有影响).
You can read the YouTrack ticket here: https://youtrack.jetbrains.com/issue/KT-7770. There's also an explanation why Kotlin needs a marker for such interfaces unlike Java (@FunctionalInterface
is only informational and has no effect on the compiler).
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