Kotlin 中的二维数组 [英] 2D Array in Kotlin

问题描述

如何在 Kotlin 中制作 2D Int 数组?我正在尝试将此代码转换为 Kotlin:

How do you make a 2D Int array in Kotlin? I'm trying to convert this code to Kotlin:

int[][] states = new int[][] {
      new int[]{-android.R.attr.state_pressed}, // not pressed
      new int[] { android.R.attr.state_pressed}  // pressed
};
int[] colors = new int[] {
      foregroundColor,
      accentColor,
      accentColor
};
ColorStateList myList = new ColorStateList(states, colors);

这是我尝试过的一次尝试，其中第一个二维数组不起作用，但我让一维数组起作用:

Here is one attempt I tried, where the first 2D array didn't work, but I got the 1D array to work:

//This doesn't work:
var states: IntArray = intArrayOf(
    intArrayOf(-android.R.attr.state_pressed), // not pressed
    intArrayOf(android.R.attr.state_pressed)  // pressed
);
//This array works:
var colors: IntArray = intArrayOf(
    foregroundColor,
    accentColor,
    accentColor
);
val myList: ColorStateList = ColorStateList(states, colors);

推荐答案

您正试图将 IntArrays 放入另一个数组中以使其成为二维数组.该数组的类型不能是 intArray，这就是失败的原因.用 arrayOf 而不是 intArrayOf 包裹你的初始数组.

You are trying to put your IntArrays inside another array to make it 2-dimensional. The type of that array cannot be intArray, which is why this fails. Wrap your initial arrays with arrayOf instead of intArrayOf.

val even: IntArray = intArrayOf(2, 4, 6)
val odd: IntArray = intArrayOf(1, 3, 5)

val lala: Array<IntArray> = arrayOf(even, odd)

这篇关于Kotlin 中的二维数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！