GetImageSize() 不应该返回 FALSE [英] GetImageSize() not returning FALSE when it should

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本文介绍了GetImageSize() 不应该返回 FALSE的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在这里处理一个小的上传脚本.我正在尝试检查上传的图像是否真的是图像,而不仅仅是重命名的 PHP 文件.

Working on a little upload script here. I'm trying to check if the uploaded image really is an image and not just a renamed PHP file.

发布脚本后,我可以使用

When the script is posted I can print the array with

foreach ($_FILES['images']['name'] as $key => $value){             
        print_r(getimagesize($_FILES['images']['tmp_name'][$key]));

这工作得很好,所以它不会返回 false.但即使我上传了一个不是图像的文件,它也不会出错.它什么都不返回,我的脚本的其余部分只是像处理图像一样处理.

That works just fine, so it won't return false. But even if I upload a file that is not an image, it won't give false. It just returns nothing at all, and the rest of my script just processes the thing like an image.

谁能告诉我我做错了什么?

Could anyone tell me what I am doing wrong?

推荐答案

上传

你不能直接在 $_FILES['images']['tmp_name'][$key] 上使用 getimagesize .. 你需要把它复制到你的系统中在你可以使用它之前先

Upload

you can not use getimagesize on $_FILES['images']['tmp_name'][$key] directly .. you need to copy it into your system first before you can use it

暂时使用$_FILES['images']['size'][$key]

  move_uploaded_file($_FILES['images']['tmp_name'][$key], $destination);
  print_r(getimagesize($destination));

假图

请注意$_FILES['images']['type'][$key]是可以伪造的

使用假图片标题

例子

file_put_contents("fake.png", base64_decode('iVBORw0KGgoAAAANSUhEUgAAAAEAAAABAQMAAAAl21bKAAAABGdBTUEAALGPC/xhBQAAAAZQTFRF////
AAAAVcLTfgAAAAF0Uk5TAEDm2GYAAAABYktHRACIBR1IAAAACXBIWXMAAAsSAAALEgHS3X78AAAAB3RJTUUH0gQCEx05cq
KA8gAAAApJREFUeJxjYAAAAAIAAUivpHEAAAAASUVORK5CYII='));

上传fake.png

array
  'name' => 
    array
      0 => string 'fake.png' (length=8)
  'type' => 
    array
      0 => string 'image/png' (length=9)
  'tmp_name' => 
    array
      0 => string 'C:Apachexampp	mpphp44F.tmp' (length=30)
  'error' => 
    array
      0 => int 0
  'size' => 
    array
      0 => int 167

验证图片

用法

var_dump ( getimagesizeReal ( "fake.png" ) );

使用的函数

function getimagesizeReal($image) {

    $imageTypes = array (
            IMAGETYPE_GIF,
            IMAGETYPE_JPEG,
            IMAGETYPE_PNG,
            IMAGETYPE_SWF,
            IMAGETYPE_PSD,
            IMAGETYPE_BMP,
            IMAGETYPE_TIFF_II,
            IMAGETYPE_TIFF_MM,
            IMAGETYPE_JPC,
            IMAGETYPE_JP2,
            IMAGETYPE_JPX,
            IMAGETYPE_JB2,
            IMAGETYPE_SWC,
            IMAGETYPE_IFF,
            IMAGETYPE_WBMP,
            IMAGETYPE_XBM,
            IMAGETYPE_ICO 
    );
    $info = getimagesize ( $image );
    $width = @$info [0];
    $height = @$info [1];
    $type = @$info [2];
    $attr = @$info [3];
    $bits = @$info ['bits'];
    $channels = @$info ['channels'];
    $mime = @$info ['mime'];

    if (! in_array ( $type, $imageTypes )) {
        return false; // Invalid Image Type ;
    }
    if ($width <= 1 && $height <= 1) {
        return false; // Invalid Image Size ;
    }

    if($bits === 1)
    {
        return false; // One Bit Image .. You don't want that  ;
    }
    return $info ;
}

这篇关于GetImageSize() 不应该返回 FALSE的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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