如何使用 Jackson 反序列化 JS 日期? [英] How to deserialize JS date using Jackson?

问题描述

我从 ExtJS 得到一个日期字符串，格式为:

I'm getting a date string from ExtJS in the format:

2011-04-08T09:00:00"

"2011-04-08T09:00:00"

当我尝试反序列化这个日期时，它会将时区更改为印度标准时间(时间增加 +5:30).这就是我反序列化日期的方式:

when i try to deserialize this date, it changes the timezone to Indian Standard Time (adds +5:30 to the time) . This is how i'm deserializing the date:

SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
getObjectMapper().getDeserializationConfig().setDateFormat(dateFormat);

这样做也不会改变时区.我仍然在 IST 中得到日期:

Doing this also doesn't change the timezone. I still get the date in IST:

SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
dateFormat.setTimeZone(TimeZone.getTimeZone("GMT"));
getObjectMapper().getDeserializationConfig().setDateFormat(dateFormat);

如何在没有时区麻烦的情况下以日期的方式反序列化日期?

How do I deserialize the date in the way in which it is coming without the hassles of Timezone?

推荐答案

我找到了一个变通方法，但是我需要在整个项目中注释每个日期的 setter.有没有办法在创建 ObjectMapper 时指定格式?

I found a work around but with this I'll need to annotate each date's setter throughout the project. Is there a way in which I can specify the format while creating the ObjectMapper?

这是我所做的:

public class CustomJsonDateDeserializer extends JsonDeserializer<Date>
{
    @Override
    public Date deserialize(JsonParser jsonParser,
            DeserializationContext deserializationContext) throws IOException, JsonProcessingException {

        SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
        String date = jsonParser.getText();
        try {
            return format.parse(date);
        } catch (ParseException e) {
            throw new RuntimeException(e);
        }

    }

}

并用这个注释每个 Date 字段的 setter 方法:

And annotated each Date field's setter method with this:

@JsonDeserialize(using = CustomJsonDateDeserializer.class)

这篇关于如何使用 Jackson 反序列化 JS 日期?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！