从 C# 中的 DateTime 中提取日期部分 [英] extract the date part from DateTime in C#

问题描述

代码行 DateTime d = DateTime.Today; 导致 10/12/2011 12:00:00 AM.我怎样才能只得到日期部分.当我比较两个日期时，我需要忽略时间部分.

The line of code DateTime d = DateTime.Today; results in 10/12/2011 12:00:00 AM. How can I get only the date part.I need to ignore the time part when I compare two dates.

推荐答案

DateTime 是一种 DataType，用于存储 Date 和 Time>.但是它提供了属性来获取Date 部分.

DateTime is a DataType which is used to store both Date and Time. But it provides Properties to get the Date Part.

您可以从 Date 属性中获取日期部分.

You can get the Date part from Date Property.

http://msdn.microsoft.com/en-us/library/system.datetime.date.aspx

DateTime date1 = new DateTime(2008, 6, 1, 7, 47, 0);
Console.WriteLine(date1.ToString());

// Get date-only portion of date, without its time.
DateTime dateOnly = date1.Date;
// Display date using short date string.
Console.WriteLine(dateOnly.ToString("d"));
// Display date using 24-hour clock.
Console.WriteLine(dateOnly.ToString("g"));
Console.WriteLine(dateOnly.ToString("MM/dd/yyyy HH:mm"));   
// The example displays the following output to the console:
//       6/1/2008 7:47:00 AM
//       6/1/2008
//       6/1/2008 12:00 AM
//       06/01/2008 00:00

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