在 C 中看起来像三角形的输出 [英] Output that looks like a triangle in C

问题描述

我写了这个程序，

include <stdio.h>

int main(){
int size = 5;

int row;
int col;

  for (col=0; col<size; col++){
    for (row=0; row<col;row++){
      printf(" ");
    }

    for (row=0; row <(size-col) ; row++){
      printf("*");
    if(col<=size){
      printf("*");
      }
    }
    printf("
");
  }
  return 0;
}

它应该是一个三角形

*********
 *******
  *****
   ***
    *

但是每一行都有一个额外的 * .有什么问题?

But instead there is one extra * on every line. What is the problem?

非常感谢！

推荐答案

Mystical 有一个解决方案，可以解决您在一次迭代中打印两个星号的方式.在您的示例中使用标识符 row 和 col 也会使事情比仅使用 i 和 j 更令人困惑，尤其是因为外循环实际上是您的当前行.

Mystical has a solution to the way you're printing two asterisks an iteration. Using the identifiers row and col in your example also makes things more confusing than just i and j, especially since the outer loop is actually your current row.

你的烂摊子的另一种选择是(我希望这不是家庭作业，因为它没有被标记):

An alternative to your mess is (I'm hoping this isn't homework since it's not tagged as such):

int main(void)
{
   int size = 5;
   int i, j;

   for (i = size; i > 0; i--) {

      for (j = i; j < size; j++)
         putchar(' ');

      for (j = 0; j < i*2 - 1; j++)
         putchar('*');

      putchar('
');
   }

   return 0;
}

您也可以将 i*2 - 1 放在一个变量中，这样就不会在循环的每次迭代中计算它(除非编译器发现您没有修改 i).

You could also put i*2 - 1 in a variable so that it's not calculated at each iteration of the loop (unless the compiler sees that you're not modifying i).

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