如何从 PhoneGaps File Transfer API 检索 POST 数据 [英] How to retrieve POST data from PhoneGaps File Transfer API

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本文介绍了如何从 PhoneGaps File Transfer API 检索 POST 数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用 Phone Gaps (Cordova 2.1) 文件传输 API 将用户照片库中的图像发布到我的服务器.文件传输 API 似乎工作正常.我只是对在我的服务器上检索这些信息感到困惑.

I'm using Phone Gaps (Cordova 2.1) file transfer API to post an image from the users photo library to my server. The file transfer API seems to be working fine. I'm just puzzled about retrieving this information on my server.

理想情况下,我需要做的是检索图像,然后将其上传到我的服务器.但是,我似乎无法从文件传输中检索任何信息?

Ideally, what I need to do is retrieve the image then upload it to my server. However, I can't seem to retrieve any information from the file transfer?

我的 JavaScript 代码(发布图像数据)是:

My JavaScript code (posting image data) is:

function onDeviceReady() {

            // Retrieve image file location from specified source
            navigator.camera.getPicture(uploadPhoto,
                                        function(message) { alert('get picture failed'); },
                                        { quality: 50, 
                                        destinationType: navigator.camera.DestinationType.FILE_URI,
                                        sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY }
                                        );

        }

        function uploadPhoto(imageURI) {
            var options = new FileUploadOptions();
            options.fileKey="file";
            options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1);
            options.mimeType="image/jpeg";

            var params = {};
            params.value1 = "test";
            params.value2 = "param";

            options.params = params;

            var ft = new FileTransfer();
            ft.upload(imageURI, encodeURI("http://some.server.com/upload.php"), win, fail, options);
        }

        function win(r) {
            console.log("Code = " + r.responseCode);
            console.log("Response = " + r.response);
            console.log("Sent = " + r.bytesSent);
        }

        function fail(error) {
            alert("An error has occurred: Code = " + error.code);
            console.log("upload error source " + error.source);
            console.log("upload error target " + error.target);
        }

我的服务器端代码是:

 $paramValue = $_POST['fileKey']; //Undefined variable
 $paramValue2 = $_POST['options']; //Undefined variable
$paramValue3 = $paramValue2['fileKey'] //Undefined variable

我也试过:

//POST variable
$paramValue = $_POST['params'];
echo "Param Value1: " . $paramValue['value1']; //Should return "test"

我也试过:

//POST variable
$paramValue = $_POST['options'];
echo "Param Value1: " . $paramValue['options']['params']['value1']; //Should return "test"

我得到的只是未定义的变量错误?

All I'm getting is undefined variable errors?

任何帮助将不胜感激,谢谢!

Any help would be much appreciated, thanks!

推荐答案

On http://some.server.com 你可以有你的 /var/www/ 目录,在这个目录中你需要 upload.php 并且这个目录中的代码应该将你的图像移动到文件夹

On http://some.server.com you can have your /var/www/ directory, in this directory you need upload.php and the code in this directory should move your image to the folder

/var/www/TEST/

<?php
   print_r($_FILES);
   $new_image_name = "YEAH.jpg";
   move_uploaded_file($_FILES["file"]["tmp_name"], "/var/www/TEST/".$new_image_name);
?>

这是您唯一需要的额外东西.

That is the only extra thing you need.

先决条件:

http://some.server.com

为了清楚起见,这是 JavaScript 和 HTML,只是为了向您展示我的 upload.php 文件是如何适应的:在你的脑海中

For clarity, this is the JavaScript and HTML just to show you how my upload.php file fits in: In your head

<script type="text/javascript" charset="utf-8">

// Wait for PhoneGap to load
document.addEventListener("deviceready", onDeviceReady, false);

// PhoneGap is ready
function onDeviceReady() {
    console.log("device ready");
    // Do cool things here...
}

function getImage() {
    // Retrieve image file location from specified source
    navigator.camera.getPicture(uploadPhoto, function(message) {
                alert('get picture failed');
            },{
                quality: 50,
                destinationType: navigator.camera.DestinationType.FILE_URI,
                sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY
            }
    );

}

function uploadPhoto(imageURI) {
    var options = new FileUploadOptions();
    options.fileKey="file";
    options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1);
    options.mimeType="image/jpeg";

    var params = new Object();
    params.value1 = "test";
    params.value2 = "param";

    options.params = params;
    options.chunkedMode = false;

    var ft = new FileTransfer();
    ft.upload(imageURI, "http://some.server.com/TEST/upload.php", win, fail, options);
}

function win(r) {
    console.log("Code = " + r.responseCode.toString()+"
");
    console.log("Response = " + r.response.toString()+"
");
    console.log("Sent = " + r.bytesSent.toString()+"
");
    alert("Code Slayer!!!");
}

function fail(error) {
    alert("An error has occurred: Code = " + error.code);
}

</script>

</head>

这就是我的身体

<button onclick="getImage();">Upload a Photo</button>

这篇关于如何从 PhoneGaps File Transfer API 检索 POST 数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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