在 Dart 中获取脚本路径(PHP 中的模拟 __DIR__ 常量) [英] Get script path in Dart (analog __DIR__ constant in PHP)

问题描述

如何在 Dart 中获取当前脚本(不可执行)的路径?

How I can get path of the current script (not executable) in Dart?

例如.在 PHP 中，我们有 __DIR__ 常量，它指的是脚本目录.如果我们有两个脚本:./run.php 和 ./lib/test.php；在 ./run.php 中，我们只包含 ./lib/test.php../lib/test.php 输出 __DIR__ 中的代码.如果我们运行 ./run.php 然后我们得到输出 /path/to/lib/test.php.

For example. In PHP we have __DIR__ constant, that reffer to script directory. If we have two scripts: ./run.php and ./lib/test.php; and in ./run.php we just include ./lib/test.php. Code in ./lib/test.php output __DIR__. if we run ./run.php then we get in output /path/to/lib/test.php.

在 Dart 中我们可以获取当前运行脚本的目录，但是如何获取当前脚本的目录?

In Dart we can get directory of the current run script, but how I can get directory of the current script?

我需要这个，因为我试图从库中获取 json-file(放在库中的).

I need in this, because I'm try to get json-file (that placed in library) from the library.

我该怎么做?

推荐答案

你说过当你运行 test.dart 时，当前目录是 /path/to/lib/测试.所以你应该能够使用相对路径来打开 rules.json.路径是 ../rules/rules.json(当然，在 Windows 上，.. ules ules.json，你可以从 Platform.pathSeparator).

You've said that when you run test.dart, the current directory is /path/to/lib/tests. So you should be able to use a relative path to open rules.json. The path is ../rules/rules.json (or of course, .. ules ules.json on Windows, you can get the separator from Platform.pathSeparator).

或者，显然你可以得到一个 来自 Platform.script.

Alternately, apparently you can get a Uri for the current script (if supported by the platform) from Platform.script.

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