从 Unity 游戏在 Android 应用程序上共享图像 [英] Share Image on Android Application from Unity Game
问题描述
当玩家死亡时,我在我的游戏中截取了屏幕截图.我使用以下代码来捕获屏幕截图.
I've captured screenshot in my game when player dies. I've following code to capture screen shot.
RenderTexture rt = new RenderTexture (800, 600, 24);
MainCamera.targetTexture = rt;
Texture2D texture = new Texture2D (800, 600, TextureFormat.RGB24, false);
MainCamera.Render ();
RenderTexture.active = rt;
texture.ReadPixels (new Rect (0, 0, 800, 600), 0, 0);
MainCamera.targetTexture = null;
RenderTexture.active = null;
Destroy (rt);
byte[] bytes = texture.EncodeToPNG ();
Directory.CreateDirectory (Application.persistentDataPath + "/GameOverScreenShot");
File.WriteAllBytes (Application.persistentDataPath + "/GameOverScreenShot" + "/DiedScreenShot.png", bytes);
我正在使用以下代码获取保存的屏幕截图.
I am getting saved screenshot using following code.
byte[] bytes = File.ReadAllBytes (Application.persistentDataPath +"/GameOverScreenShot" + "/BirdDiedScreenShot.png");
Texture2D texture = new Texture2D (800, 600, TextureFormat.RGB24, false);
RectOffset tempOffset = new RectOffset (5, 5, 5, 5);
texture.filterMode = FilterMode.Trilinear;
texture.LoadImage (bytes);
Sprite sprite = Sprite.Create (texture, new Rect (0, 0, 800, 400), new Vector2 (0.5f, 0.0f), 2.0f);
ScreenShot_Image.GetComponent<Image> ().sprite = sprite;
现在,我想在 android 应用程序上分享此屏幕截图.根据我的研究,我有以下代码,但它返回空白图像.
Now, I want to share this screenshot on android application. As per my research i have got following code for that, but it is returning blank image.
//instantiate the class Intent
AndroidJavaClass intentClass = new AndroidJavaClass("android.content.Intent");
//instantiate the object Intent
AndroidJavaObject intentObject = new AndroidJavaObject("android.content.Intent");
//call setAction setting ACTION_SEND as parameter
intentObject.Call<AndroidJavaObject>("setAction", intentClass.GetStatic<string>("ACTION_SEND"));
//instantiate the class Uri
AndroidJavaClass uriClass = new AndroidJavaClass("android.net.Uri");
//instantiate the object Uri with the parse of the url's file
string destination = Application.persistentDataPath + "/GameOverScreenShot" + "/DiedScreenShot.png";
AndroidJavaObject uriObject = uriClass.CallStatic<AndroidJavaObject>("parse","file://"+destination);
//call putExtra with the uri object of the file
intentObject.Call<AndroidJavaObject>("putExtra", intentClass.GetStatic<string>("EXTRA_STREAM"), uriObject);
//set the type of file
intentObject.Call<AndroidJavaObject>("setType", "image/*");
//instantiate the class UnityPlayer
AndroidJavaClass unity = new AndroidJavaClass("com.unity3d.player.UnityPlayer");
//instantiate the object currentActivity
AndroidJavaObject currentActivity = unity.GetStatic<AndroidJavaObject>("currentActivity");
//call the activity with our Intent
currentActivity.Call("startActivity", intentObject);
我应该改变什么??请帮忙,先谢谢
What should I change in this?? Please help, Advance Thanks
推荐答案
只需调用 takeScreenShotAndShare()
即可截屏并分享.如果您已经有了要分享的图像,只需调用 StartCoroutine(shareScreenshot(path));
并传入图像的路径/位置.这仅支持 png 图像.要分享jpeg,请更改
Simply call takeScreenShotAndShare()
to take Screen Shot and share it. If you already have the image you want to share, just call StartCoroutine(shareScreenshot(path));
and pass in the path/location of the image. This only supports png images. To share jpeg, change
intentObject.Call<AndroidJavaObject>("setType", "image/png");
到
intentObject.Call<AndroidJavaObject>("setType", "image/jpeg");
完整代码:
void takeScreenShotAndShare()
{
StartCoroutine(takeScreenshotAndSave());
}
private IEnumerator takeScreenshotAndSave()
{
string path = "";
yield return new WaitForEndOfFrame();
Texture2D screenImage = new Texture2D(Screen.width, Screen.height);
//Get Image from screen
screenImage.ReadPixels(new Rect(0, 0, Screen.width, Screen.height), 0, 0);
screenImage.Apply();
//Convert to png
byte[] imageBytes = screenImage.EncodeToPNG();
System.IO.Directory.CreateDirectory(Application.persistentDataPath + "/GameOverScreenShot");
path = Application.persistentDataPath + "/GameOverScreenShot" + "/DiedScreenShot.png";
System.IO.File.WriteAllBytes(path, imageBytes);
StartCoroutine(shareScreenshot(path));
}
private IEnumerator shareScreenshot(string destination)
{
string ShareSubject = "Picture Share";
string shareLink = "Test Link" + "
http://stackoverflow.com/questions/36512784/share-image-on-android-application-from-unity-game";
string textToShare = "Text To share";
Debug.Log(destination);
if (!Application.isEditor)
{
AndroidJavaClass intentClass = new AndroidJavaClass("android.content.Intent");
AndroidJavaObject intentObject = new AndroidJavaObject("android.content.Intent");
intentObject.Call<AndroidJavaObject>("setAction", intentClass.GetStatic<string>("ACTION_SEND"));
AndroidJavaClass uriClass = new AndroidJavaClass("android.net.Uri");
AndroidJavaObject uriObject = uriClass.CallStatic<AndroidJavaObject>("parse", "file://" + destination);
intentObject.Call<AndroidJavaObject>("putExtra", intentClass.GetStatic<string>("EXTRA_STREAM"), uriObject);
intentObject.Call<AndroidJavaObject>("putExtra", intentClass.GetStatic<string>("EXTRA_TEXT"), textToShare + shareLink);
intentObject.Call<AndroidJavaObject>("putExtra", intentClass.GetStatic<string>("EXTRA_SUBJECT"), ShareSubject);
intentObject.Call<AndroidJavaObject>("setType", "image/png");
AndroidJavaClass unity = new AndroidJavaClass("com.unity3d.player.UnityPlayer");
AndroidJavaObject currentActivity = unity.GetStatic<AndroidJavaObject>("currentActivity");
currentActivity.Call("startActivity", intentObject);
}
yield return null;
}
这篇关于从 Unity 游戏在 Android 应用程序上共享图像的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!