如何在指定文件中运行测试用例? [英] How to run test cases in a specified file?

问题描述

我的包测试用例分散在多个文件中，如果我运行 go test 它会运行包中的所有测试用例.

My package test cases are scattered across multiple files, if I run go test <package_name> it runs all test cases in the package.

虽然没有必要运行所有这些.有没有办法指定一个文件让 go test 运行，让它只运行文件中定义的测试用例?

It is unnecessary to run all of them though. Is there a way to specify a file for go test to run, so that it only runs test cases defined in the file?

推荐答案

有两种方法.最简单的方法是使用 -run 标志并提供一个模式匹配您要运行的测试的名称.示例:

There are two ways. The easy one is to use the -run flag and provide a pattern matching names of the tests you want to run. Example:

go test packageName -run NameOfTest

有关详细信息，请参阅文档.请注意，-run 标志也可能运行其他包含字符串的测试NameOfTest，因为 -run 标志匹配正则表达式.所以为了确保只有一个运行名为NameOfTest"的测试，必须使用正则表达式 ^NameOfTest$:

See the docs for more info. Note that the -run flag may also run other tests if they contain the string NameOfTest, as the -run flag matches a regexp. So to ensure that only a test named exactly 'NameOfTest' is run, one has to use the regexp ^NameOfTest$:

go test -run "^NameOfTest$" 

另一种方法是命名特定文件，其中包含您要运行的测试:

The other way is to name the specific file, containing the tests you want to run:

go test -v foo_test.go

但是有一个问题.这在以下情况下运行良好:

But there's a catch. This works well if:

• foo.go 在 package foo 中.
• foo_test.go 在 package foo_test 中并导入 'foo'.

• foo.go is in package foo.
• foo_test.go is in package foo_test and imports 'foo'.

如果 foo_test.go 和 foo.go 是同一个包(常见情况)，那么你必须命名构建 foo_test 所需的所有其他文件.在这个例子中将是:

If foo_test.go and foo.go are the same package (a common case) then you must name all other files required to build foo_test. In this example it would be:

go test foo_test.go foo.go

我建议使用 -run 模式.或者，在可能的情况下，始终运行所有包测试.

I'd recommend to use the -run pattern. Or, where/when possible, always run all package tests.

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