Spring security 4 自定义登录 j_spring_security_check 返回http 302 [英] Spring security 4 custom login j_spring_security_check return http 302
本文介绍了Spring security 4 自定义登录 j_spring_security_check 返回http 302的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在这里
初始化器
public class AppInitializer extends
AbstractAnnotationConfigDispatcherServletInitializer {
@Override
protected Class<?>[] getRootConfigClasses() {
return new Class[] { SecurityConfig.class };
}
@Override
protected Class<?>[] getServletConfigClasses() {
return new Class[] { MvcConfig.class };
}
@Override
protected String[] getServletMappings() {
return new String[] { "/" };
}
}
mvc 配置
@EnableWebMvc
@ComponentScan({ "com.appname.controller" })
public class MvcConfig extends WebMvcConfigurerAdapter {
@Bean
public InternalResourceViewResolver viewResolver() {
InternalResourceViewResolver resolver = new InternalResourceViewResolver();
resolver.setPrefix("/WEB-INF/jsp/");
resolver.setSuffix(".jsp");
return resolver;
}
@Override
public void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("/res/**").addResourceLocations("/res/");
}
}
安全配置
@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled = true, jsr250Enabled = true)
public class SecurityConfig extends WebSecurityConfigurerAdapter {
private CustomUserDetailsService customUserDetailsService;
public SecurityConfig() {
customUserDetailsService = new CustomUserDetailsService();
}
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth)
throws Exception {
auth.inMemoryAuthentication().withUser("user").password("password")
.roles("USER");
auth.userDetailsService(customUserDetailsService);
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests()
.antMatchers("/res/**").permitAll()
.and().authorizeRequests()
.anyRequest().hasRole("USER")
.and().formLogin().loginPage("/account/signin").permitAll()
.and().logout().permitAll();
}
}
安全初始化程序
public class SecurityInitializer extends
AbstractSecurityWebApplicationInitializer {
}
自定义登录
public class CustomUserDetailsService implements UserDetailsService {
private AccountRepository accountRepository;
public CustomUserDetailsService() {
this.accountRepository = new AccountRepository();
}
@Override
public UserDetails loadUserByUsername(String email)
throws UsernameNotFoundException {
Account account = accountRepository.getAccountByEmail(email);
if (account == null) {
throw new UsernameNotFoundException("Invalid email/password.");
}
Collection<GrantedAuthority> authorities = new ArrayList<GrantedAuthority>();
authorities.add(new SimpleGrantedAuthority("USER"));
return new User(account.getEmail(), account.getPassword(), authorities);
}
}
但是，现在我有关于自定义登录的新问题.
However, now I have new issue about custom login.
发布到 j_spring_security_check 时，我会收到 http 302.
when post to j_spring_security_check, I will receive http 302.
我正在请求/，但在登录后，它停留在登录页面上.
I'm requesting /, but after sign in, it stays on the sign in page.
因为我使用的是 spring security 4.x 版本，并且纯粹是基于代码的配置，所以我在互联网上找不到更多参考.谁能帮忙找出原因.
Because I'm using spring security 4.x version, and purely code based configuration, so I can't find more reference on internet. Can anyone help to figure out why.
编辑
org.springframework.beans.factory.BeanCreationException:
Error creating bean with name 'securityConfig':
Injection of autowired dependencies failed;
nested exception is org.springframework.beans.factory.BeanCreationException:
Could not autowire field:
private org.springframework.security.core.userdetails.UserDetailsService sg.mathschool.infra.SecurityConfig.userDetailsService;
nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException:
No qualifying bean of type [org.springframework.security.core.userdetails.UserDetailsService] found for dependency:
expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations:
{@org.springframework.beans.factory.annotation.Autowired(required=true), @org.springframework.beans.factory.annotation.Qualifier(value=userDetailsService)}
我改变了CustomUserDetailsService
@Service("userDetailsService")
public class CustomUserDetailsService implements UserDetailsService {
private AccountRepository accountRepository;
public CustomUserDetailsService() {
this.accountRepository = new AccountRepository();
}
@Override
@Transactional(readOnly = true)
public UserDetails loadUserByUsername(String email)
throws UsernameNotFoundException {
Account account = accountRepository.getAccountByEmail(email);
if (account == null) {
throw new UsernameNotFoundException("Invalid email/password.");
}
Collection<GrantedAuthority> authorities = new ArrayList<GrantedAuthority>();
authorities.add(new SimpleGrantedAuthority("USER"));
return new User(account.getEmail(), account.getPassword(), authorities);
}
}
和安全配置
@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled = true, jsr250Enabled = true)
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
@Qualifier("userDetailsService")
private UserDetailsService userDetailsService;
@Autowired
public void configureGlobal(AuthenticationManagerBuilder auth)
throws Exception {
auth.inMemoryAuthentication().withUser("user").password("password")
.roles("USER");
auth.userDetailsService(userDetailsService).passwordEncoder(
passwordEncoder());
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests().antMatchers("/res/**").permitAll()
.antMatchers("/account/**").permitAll().anyRequest()
.hasRole("USER").and().formLogin().loginPage("/account/signin")
.failureUrl("/account/signin?error").usernameParameter("email")
.passwordParameter("password").and().logout()
.logoutSuccessUrl("/account/signin?logout").and().csrf();
}
@Bean
public PasswordEncoder passwordEncoder() {
PasswordEncoder encoder = new BCryptPasswordEncoder();
return encoder;
}
}
推荐答案
在 Spring Security 4.x 中，登录 URL 已更改为 login 而不是 j_spring_security_check，请参阅
In Spring Security 4.x login URL has changed to login instead of j_spring_security_check, see Migrating from Spring Security 3.x to 4.x (XML Configuration).
<form name='f'action="login" method='POST'>
<input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}" />
<table>
<tbody>
<tr>
<td>User Name</td>
<td><input type="text" name="username" size="30" /></td>
</tr>
<tr>
<td>Password</td>
<td><input type="password" name="password" size="30" /></td>
</tr>
<tr>
<td></td>
<td><input type="submit" value="login" /></td>
</tr>
</tbody>
</table>
</form>
这篇关于Spring security 4 自定义登录 j_spring_security_check 返回http 302的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
