Python 如果有很多或以契约形式 [英] Python if with many or in a contracted form
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问题描述
我正在学习 python,我发现自己在尝试创建一个 if 语句时失败了,如果用户输入 y 或 yes,该语句应该为真.
I'm learning python and I found myself lost trying to create a an if statement that should be true if the user input y or yes.
#!/usr/bin/env python3
user_input = input('Would you like to go on?')
lowui = user_input.lower
if lowui == ('y' or 'yes'):
print('You want to go on')
else
print('See you later, bye')
问题是只有当我输入 y 而不是 yes 时它才会变成真的.如果我删除括号,它总是错误的.好的,我可以做一个像
The problem is that it becomes true only if I type y but not for yes. If I remove the parenthesis it becomes always false. Ok, I can do a workaround like
if lowui == 'y' or lowui == 'yes':
但我想知道是否有任何技巧可以不强迫我多次写入变量.
提前致谢.
but I was wondering if there is any trick that don't force me to write so many times tha variable.
Thank you in advance.
推荐答案
改为
if lowui in ('y', 'yes'):
这也是错误的:
lowui = user_input.lower
应该是:
lowui = user_input.lower() # Actually call the lower function
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