如何检查一个数字是否在shell中的范围内 [英] How to check if a number is within a range in shell
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问题描述
我只想在两个值之间插入数字,否则脚本会重复直到正确的数字.
I want to just insert number between two values, and otherwise the script repeated until correct number.
这是我的脚本,它不能正常工作:
This is my script and it does not work correctly:
validation(){
read number
if [ $number -ge 2 && $number -ls 5 ]; then
echo "valid number"
break
else
echo "not valid number, try again"
fi
}
echo "insert number"
validation
echo "your number is" $number
推荐答案
如果您使用 Bash,最好使用算术表达式 ((...))
以提高可读性和灵活性:
If you are using Bash, you are better off using the arithmetic expression, ((...))
for readability and flexibility:
if ((number >= 2 && number <= 5)); then
# your code
fi
循环读取直到输入有效数字:
To read in a loop until a valid number is entered:
#!/bin/bash
while :; do
read -p "Enter a number between 2 and 5: " number
[[ $number =~ ^[0-9]+$ ]] || { echo "Enter a valid number"; continue; }
if ((number >= 2 && number <= 5)); then
echo "valid number"
break
else
echo "number out of range, try again"
fi
done
((number >= 2 && number <= 5))
也可以写成 ((2 <= number <= 5))代码>.
另见:
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