仅从此元素中提取文本，而不是其子元素 [英] Only extracting text from this element, not its children
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问题描述
我只想从汤的最顶层元素中提取文本；然而，soup.text 也给出了所有子元素的文本:
我有
导入 BeautifulSoup汤=BeautifulSoup.BeautifulSoup('<html>是<b>否</b></html>')打印汤.text对此的输出是yesno.我只想说是".
实现这一目标的最佳方法是什么?
编辑:我也希望在解析 'no</b>yes</html> 时输出 yes'.
解决方案
.find(text=True) 怎么样?
我想我现在明白你想要什么了.试试这个:
<预><代码>>>>BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').html.find(text=True, recursive=False)你是的>>>BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').html.find(text=True, recursive=False)你是的I want to extract only the text from the top-most element of my soup; however soup.text gives the text of all the child elements as well:
I have
import BeautifulSoup
soup=BeautifulSoup.BeautifulSoup('<html>yes<b>no</b></html>')
print soup.text
The output to this is yesno. I want simply 'yes'.
What's the best way of achieving this?
Edit: I also want yes to be output when parsing '<html><b>no</b>yes</html>'.
解决方案
what about .find(text=True)?
>>> BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').find(text=True)
u'yes'
>>> BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').find(text=True)
u'no'
EDIT:
I think that I've understood what you want now. Try this:
>>> BeautifulSoup.BeautifulSOAP('<html><b>no</b>yes</html>').html.find(text=True, recursive=False)
u'yes'
>>> BeautifulSoup.BeautifulSOAP('<html>yes<b>no</b></html>').html.find(text=True, recursive=False)
u'yes'
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