以有效的方式将 XML 解析为 JAVA POJO [英] Parse XML TO JAVA POJO in efficient way

问题描述

如何以有效的方式为下面的 xml 解析和创建 java pojo?请建议任何有效的解析器.

How to parse and create java pojo for below xml in an efficient way? Kindly suggest any efficient parser.

XML 格式为

<?xml version="1.0" encoding="utf-8"?>
<CCMainRootTag ID="12">
  <Header TableName="TableName"    TableVersion="12" TableID="12" CreatedDate="2013-02-09T15:35:33" CreatedByUserName="ABC" CreatedBySystem="ABC" />
  <ClassPrimary ID="12" Code="Y" DescriptionDK="DK language " DescriptionUK="" DefDK="" DefUK="" IFDGUID="">
    <ObjectClass ID="12" Code="YA" DescriptionDK="DK Language" DescriptionUK="" DefDK=""     DefUK="" IFDGUID="">
      <Synonym>
        <Concept Description="Description" Language="DK" />
        <Concept Description="" Language="UK" />
        <Concept Description="Description" Language="DK" />
        <Concept Description="" Language="UK" />
        <Concept Description="Description" Language="DK" />
        <Concept Description="" Language="UK" />
        <Concept Description="Description" Language="DK" />
        <Concept Description="" Language="UK" />
      </Synonym>
    </ObjectClass>
    <ObjectClass ID="12" Code="YB" DescriptionDK="DK Language" DescriptionUK="" DefDK="" DefUK="" IFDGUID=""> </ObjectClass>
    <ObjectClass ID="12" Code="YC" DescriptionDK="DK Language" DescriptionUK="" DefDK="" DefUK="" IFDGUID=""> </ObjectClass>
    <ObjectClass ID="12" Code="YD" DescriptionDK="DK language" DescriptionUK="" DefDK="" DefUK="" IFDGUID=""> </ObjectClass>
  </ClassPrimary>
</CCMainRootTag>

我已经使用了这个链接，但它的性能很慢并且有问题无效pojo.

I already use thisLink but it have slow performance and having problem did't valid pojo.

我想以一种有效的方式为我提供直接的 java pojo 的解析器.

I want to parser which provide me direct java pojo in a efficient way.

推荐答案

您可以使用 JAXB 将 XML 转换为 Java POJO.但在您最终确定解决方案之前检查此站点以进行性能比较.

You can use JAXB to convert XML into Java POJOs. But before you finalize the solution check this site for performance comparison.

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