使用简单的对话框在 Python 中选择文件 [英] Choosing a file in Python with simple Dialog

问题描述

我想在我的 Python 控制台应用程序中获取文件路径作为输入.

I would like to get file path as input in my Python console application.

目前我只能在控制台中要求完整路径作为输入.

Currently I can only ask for full path as an input in the console.

有没有办法触发一个简单的用户界面，让用户可以选择文件而不是输入完整路径?

Is there a way to trigger a simple user interface where users can select file instead of typing the full path?

推荐答案

使用 tkinter 怎么样?

How about using tkinter?

from Tkinter import Tk     # from tkinter import Tk for Python 3.x
from tkinter.filedialog import askopenfilename

Tk().withdraw() # we don't want a full GUI, so keep the root window from appearing
filename = askopenfilename() # show an "Open" dialog box and return the path to the selected file
print(filename)

完成！

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