如何将列表的每个元素分配给一个单独的变量? [英] How to assign each element of a list to a separate variable?

问题描述

如果我有一个清单，请说:

if I have a list, say:

ll = ['xx','yy','zz']

并且我想将此列表的每个元素分配给一个单独的变量:

and I want to assign each element of this list to a separate variable:

var1 = xx
var2 = yy
var3 = zz

不知道列表有多长，我该怎么做?我试过了:

without knowing how long the list is, how would I do this? I have tried:

max = len(ll)
count = 0
for ii in ll:
    varcount = ii
    count += 1
    if count == max:
        break

我知道 varcount 不是创建动态变量的有效方法，但我想要做的是创建 var0、var1、var2、var3 等基于计数的内容.

I know that varcount is not a valid way to create a dynamic variable, but what I'm trying to do is create var0, var1, var2, var3 etc based on what the count is.

:

没关系，我应该开始一个新问题.

Never mind, I should start a new question.

推荐答案

一般来说，不推荐对大量列表元素/变量使用那种编程.

Generally speaking, it is not recommended to use that kind of programming for a large number of list elements / variables.

但是，以下语句可以正常工作并且符合预期

However, the following statement works fine and as expected

a,b,c = [1,2,3]

这称为解构".

在某些情况下，它可以为您节省一些代码行，例如我有 a,b,c 作为整数并希望它们的字符串值为 sa,sb,sc:

It could save you some lines of code in some cases, e.g. I have a,b,c as integers and want their string values as sa,sb,sc:

sa, sb,sc = [str(e) for e in [a,b,c]]

或者更好

sa, sb,sc = map(str, (a,b,c) )

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